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3 years ago

9

7 is divided by a number. As an expression

1 answer:

kakasveta [241]3 years ago

6 0

Answer:

7 ÷ x

Step-by-step explanation:

You might be interested in

What is the solution to –2(8x – 4) < 2x + 5?

RSB [31]

Simplify both sides of the inequality.

−16x+8<2x+5

Subtract 2x from both sides.

−16x+8−2x<2x+5−2x

−18x+8<5

Subtract 8 from both sides.

−18x+8−8<5−8

−18x<−3

Divide both sides by -18.

−18x/−18 < −3/−18

x>16

Ans : x > 16

7 0

3 years ago

Read 2 more answers

Find the area of the shaded region. All angles are right angles.

Tanzania [10]

Answer: 147

Step-by-step explanation:

First, 9 x 4 = 36

Again, 9 x 4 = 36

Finally 15 x 5 = 75

So, 36 + 36 + 75 = 147

8 0

4 years ago

You drop a ball from a height of 0.5 meters. Each curved path has 52% of the height of the previous path. a. Write a rule for th

Verizon [17]

Answer:

a) $a_n = 50 (0.52) ^ {n-1}$

b) $a_6 = 50 (0.52) ^ 5 = 1.90\ cm$

Step-by-step explanation:

If each curved path has 52% of the previous height this means that $\frac{a_{n+1}}{a_n} = 0.52$

Then the radius of convergence is 0.52 and this is a geometric series.

The geometric series have the form:

$a_n = a_1 (r) ^ {n-1}$

Where

$a_1$ is the first term of the series and r is the radius of convergence.

In this problem

$a_1 = 0.5$ meters = 50 cm

$r = 0.52$

a) Then the rule for the sequence is:

$a_n = 50 (0.52) ^ {n-1}$

b) we must calculate $a_6$

$a_6 = 50 (0.52) ^ 6-1\\\\a_6 = 50 (0.52) ^ 5 = 1.90\ cm$

3 0

3 years ago

The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0). Which type of triangle is ∆ABC? Select All that apply.

stepan [7]

Given:

The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0).

To find:

The type of the given triangle.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the distance formula, we get

$AB=\sqrt{(5-(-3))^2+(8-2)^2}$

$AB=\sqrt{(8)^2+(6)^2}$

$AB=\sqrt{64+36}$

$AB=\sqrt{100}$

$AB=10$

Similarly,

$BC=\sqrt{(11-5)^2+(0-8)^2}$

$BC=\sqrt{(6)^2+(8)^2}$

$BC=\sqrt{36+64}$

$BC=\sqrt{100}$

$BC=10$

And,

$AC=\sqrt{(11-(-3))^2+(0-2)^2}$

$AC=\sqrt{(14)^2+(-2)^2}$

$AC=\sqrt{196+4}$

$AC=\sqrt{200}$

$AC=10\sqrt{2}$

Two sides of the triangle are equal, i.e., $AB=BC$ . So, the triangle is an isosceles triangle.

Sum of square of two smaller side is

$AB^2+BC^2=10^2+10^2$

$AB^2+BC^2=100+100$

$AB^2+BC^2=200$

$AB^2+BC^2=AC^2$

Using the Pythagoras theorem, we can say that the given triangle is a right triangle.

Therefore, the correct options are B and F.

7 0

3 years ago

wariber [46]

Answer: 50w+150>650

w>10

Step-by-step explanation: Subtract 150 on both sides, leaving 50w>500. Divide both sides by 50 to get w>10

3 0

3 years ago