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Westkost [7]
3 years ago
10

Calculate the slope of the line.Please help and explain

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
5 0
Slope= rise/run
which is 4/2
4 decided by 2 is 2
so the slope is 2. also i LOVE ur pfp :)))
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Yesterday, the price of a loaf of bread at five supermarkets was $1.44, $1.59, $1.69, $1.47, and $1.61, but today each supermark
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\frac{1.49+1.64+1.74+1.52+1.66}{5}
=\frac{8.05}{5} =1.61
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3 years ago
Equation of a straight line (see attached)
Viefleur [7K]

Answer:

y = 2x - 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = A(4, 7) and (x₂, y₂ ) = B(2,3)

m = \frac{3-7}{2-4} = \frac{-4}{-2} = 2 , thus

y = 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (2, 3), then

3 = 4 + c ⇒ c = 3 - 4 = - 1

y = 2x - 1 ← equation of line

8 0
3 years ago
Read 2 more answers
Help!! Plzzz
Roman55 [17]

Answer:

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3 years ago
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aliya0001 [1]

Answer: (2, -3)

Step-by-step explanation: (2, -3) is the new ordered pair rotated 270°

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3 years ago
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A principal of ​$6000 is invested in an account paying an annual rate of 5​%. Find the amount in the account after 4 years if th
astra-53 [7]

Solution :

Given :

Principal amount deposited, P = $ 6000

Rate of interest, r = 5%

Number of years, t = 4 years

When the deposited amount is compounded semiannually, i.e. n = 2

Therefore,

Future value,

$FV = P\left( 1 +\frac{r}{n}\right)^{nt}$

$FV = 6000\left( 1 +\frac{0.05}{2}\right)^{2 \times 4}$

$FV = 6000 \times (1.025)^8$

       = 6000 x 1.2184

        = 7310.4

Therefore, after 4 years there will be $ 7310.4 in the amount when compounded semi annually.

When the deposited amount is compounded quarterly, i.e. n = 4

Therefore,

Future value,

$FV = P\left( 1 +\frac{r}{n}\right)^{nt}$

$FV = 6000\left( 1 +\frac{0.05}{4}\right)^{4 \times 4}$

$FV = 6000 \times (1.0125)^{16}$

       = 6000 x 1.219889

        = 7319.334

Therefore, after 4 years there will be $ 7319.334 in the amount when compounded quarterly.

When the deposited amount is compounded monthly, i.e. n = 12

Therefore,

Future value,

$FV = P\left( 1 +\frac{r}{n}\right)^{nt}$

$FV = 6000\left( 1 +\frac{0.05}{12}\right)^{12 \times 4}$

$FV = 6000 \times (1.0041667)^{48}$

       = 6000 x 1.22089

        = 7325.34

Therefore, after 4 years there will be $ 7325.34 in the amount when compounded monthly.

8 0
3 years ago
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