All categories

3 years ago

What do I write plz help people

Mathematics

1 answer:

erastovalidia [21]3 years ago

7 0

Imagine you are a close friend/ relative to Shakespeare and write how you view him

You might be interested in

Negative three over four times five over seven divided by negative one over two

LekaFEV [45]

Answer:

$1 \frac{1}{14}$

Step-by-step explanation:

$- \frac{3}{4} \times \frac{5}{7} \div - \frac{1}{2} = - \frac{15}{28} \times -2 = \frac{30}{28} = 1 \frac{2}{28} = 1 \frac{1}{14}$

I am joyous to assist you anytime.

5 0

3 years ago

Multiply (x^2+4x+2) (2x^2+3x-4)

algol13

Answer:

(x² + 4x + 2)(2x² + 3x - 4) equals 2x⁴ + 11x³ + 12x² - 10x - 8

Step-by-step explanation:

(x² + 4x + 2)(2x² + 3x - 4)

Multiply each term in the first parentheses into the expression in the second parentheses.

2x⁴ + 3x³ - 4x² + 8x³ + 12x² - 16x + 4x² + 6x - 8

Combine like terms.

2x⁴ + 11x³ + 12x² - 10x - 8

So, your answer would be letter choice B.

6 0

3 years ago

Read 2 more answers

Leah wrote 2 different fractions with the same denominator. both fractions were less than 1. can their sum equal 1? explain

grandymaker [24]

Yes. Their sum can be equal to 1 because if they have the same denominator they will add easier like 3/4 and 1/4 or 1/2 and 1/2. All of them have the same denominator and still equal 1

8 0

3 years ago

Do 9a, 9b, 9c please quick due in 5 minutes also pleaseeee show step by step thanks I will mark brainlest and give extra points

Sloan [31]

Step-by-step explanation:

The answer to 9a is that A and B have to be on the right side of the number line but A has to be greater than B.

The first and second box for 9c is > .

8 0

3 years ago

Electric charge is distributed over the disk x2 + y2 ≤ 16 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y

professor190 [17]

Answer:

Required total charge is $256\pi$ coulombs per square meter.

Step-by-step explanation:

Given electric charge is dristributed over the disk,

$x^2=y^2\leq 16$ so that the charge density at (x,y) is,

$\rho (x,y)=2x+2y+2x^2+2y^2$

To find total charge on the disk let Q be the total charge and $x=r\cos\theta,y=r\sin\theta$ so that,

$Q={\int\int}_Q\rho(x,y) dA$ where A is the surface of disk.

$=\int_{0}^{2\pi}\int_{0}^{4}(2x+2y+2x^2+2y^2)dA$

$=\int_{0}^{2\pi}\int_{0}^{4}(2r\cos\theta+2r\sin\theta+2r^2 \cos^{2}\theta+2r^2\sin^2\theta)rdrd\theta$

$=2\int_{0}^{2\pi}\int_{0}^{4}r^2(\cos\theta+\sin\theta)drd\theta+2\int_{0}^{2\pi}\int_{0}^{4}r^3drd\theta$

$=\frac{2}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)\Big[r^3\Big]_{0}^{4}d\theta+2\int_{0}^{2\pi}\Big[\frac{r^4}{4}\Big]d\theta$

$=\frac{128}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)d\theta+128\int_{0}^{2\pi}d\theta$

$=\frac{128}{3}\Big[\sin\theta-\cos\theta\Big]_{0}^{2\pi}+128\times 2\pi$

$=\frac{128}{3}\Big[\sin 2\pi-\cos 2\pi-\sin 0+\cos 0\Big]+256\pi$

$=256\pi$

Hence total charge is $256\pi$ coulombs per square meter.

3 0

3 years ago