Answer:
Explanation:
The following is written in Java. It uses File input, to get the file and read every line in the file. It adds all the lines into a variable called fullString. Then it uses regex to split the string into separate words. Finally, it maps the words into an array that counts all the words and how many times they appear. A test case has been created and the output can be seen in the attached image below. Due to technical difficulties I have added the code as a txt file below.
Assuming the name of your data frame is flavors_df, the code chunk which will allow review of the structure of the data frame is colnames(flavors_df).
<h3>
What is Code chunk?</h3>
This is referred to a a runable piece of R code and helps to reduce incidents of mismatch pertaining to the commentary in a paper and the results being discussed.
In the case of a data frame which is flavors_df, the appropriate code chunk is colnames(flavors_df) which allow for extensive review of the item with the barest minimal error which is why it was chosen as the most appropriate choice.
Read more about Code chunk here brainly.com/question/25525005
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A diagram which indicates the sequence in which milk travels through a production plant to each stage of a cheese manufacturing process is: D. A process schedule
<h3>What is a
process schedule?</h3>
A process schedule can be defined as a type of diagram (schematic) which is designed and developed to illustrate the various processes and stages (steps) that are associated with manufacturing of a particular product.
In this context, a process schedule is a diagram which would most likely indicate the sequence in which milk travels through a production plant to each stage of a cheese manufacturing process.
Read more on cheese manufacturing here: brainly.com/question/21148228
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Answer:
Explanation:
Well here you only have to add 2 new horses .... so simply what you can do is find 2 slots where the gap is maximum ... lets take the given example in detail to understand the same.... here 10001001000010 here you can observe that the difference between the first two filled slots is 3 then 2 then 4 then 1....... make it a separate array ...... now as i said that we just need to place two new horses so we just need two of the biggest numbers from this array and place the new horses at the center of the corresponding slots ... like here 3 and 4 are greatest ... so one horse is placed in between the gap corresponding to 3 while other at 4 ..... after making the new array answer can be find in linear time itself... I hope this makes sense ....
Now lets understand how to program it easily so firstly after scanning all stuff ..... we will make a gap array .... then just think now what we will do is find the greatest two numbers then again putting the horses and then find our answers .... so now an easy approach is that instead of making the string again and again searching for answer .... what we do is just do half of the two greatest ones and again find the greatest one in array....
