Answer:
Don't answer him because you don't know what he is going to do
Answer:
li=list(map(str,input().strip().split()))#taking input of the string.
#swapping first and last element.
temp=li[0]
li[0]=li[-1]
li[-1]=temp
print(li)#printing the list.
Explanation:
I have taken the list li for taking the input of strings.Then after that swapping first and last element of the list.Then printing the list.
This is to much work for 5 points cmon
Answer:
False.
Explanation:
When we declare a variable as reference type we have to initialize that variable otherwise the compiler will give error that the reference variable is not initialized.You also cannot initialize the variable Foo& with NULL value because it is a reference variable and we have to initialize it.
On the other there is no need to initialize the variable Foo * since it is a pointer it can also store NULL value.
So the answer is only Foo* can store NULL value not Foo &.
