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Papessa [141]
3 years ago
5

How efficient would a 6-bit code be in asynchronous transmission if it had 1 parity bit, 1 start bit, and 2 stop bits?

Computers and Technology
1 answer:
Lana71 [14]3 years ago
7 0
How efficient well if we are transmitting 6bits and we need 10 to transmit the 6 bits that would be 6/10 = .6 = 60% efficient.
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11 of the 25 people on the bus get off at the first stop. What percent best represents the portion of the bus that got off on th
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Answer:

44%

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In a(n) ____, the programmer uses a programming language (in context free grammar) to tell the computer what to accomplish and h
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3 years ago
Java Eclipse homework. I need help coding this
olganol [36]

Answer:

I can't just do your project but use this as a head start.

Explanation:

public class TableOfBases

{

   public static void main(String[] args)

   {

       // print out "Decimal    Binary   Octal   Hex    Character";

       //  write a for loop from 65 to 90

       for (int i ...  ) {

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         // get a string for integer i with base 8

           String octal = Integer.toString( ...   );

         // get a string for integer i with base 16

           String hex =  ...

        // get a char for a chararater that has ASCII code i

           char ch = (char) i ;

         // print out binary, octal and hex, and ch

       }

   }

}

/*

Project... Basically Speaking

Create a project called TableOfBases with class Tester.

The main method should have a for loop that cycles through the integer values

65 <= j <= 90 (These are the ASCII codes for characters A – Z).

Use the methods learned in this lesson to produce a line of this table on each pass

through the loop. Display the equivalent of the decimal number in the various bases

just learned (binary, octal, and hex) as well as the character itself:

Decimal Binary Octal Hex Character

65 1000001 101 41 A

66 1000010 102 42 B

67 1000011 103 43 C

68 1000100 104 44 D

69 1000101 105 45 E

70 1000110 106 46 F

....

71 1000111 107 47 G 72 1001000 110 48 H 73 1001001 111 49 I 74 1001010 112 4a J 75 1001011 113 4b K 76 1001100 114 4c L 77 1001101 115 4d M 78 1001110 116 4e N 79 1001111 117 4f O 80 1010000 120 50 P 81 1010001 121 51 Q 82 1010010 122 52 R 83 1010011 123 53 S 84 1010100 124 54 T 85 1010101 125 55 U 86 1010110 126 56 V 87 1010111 127 57 W 88 1011000 130 58 X 89 1011001 131 59 Y 90 1011010 132 5a Z

*/

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