Which table of values was used to create the scatterplot below?
1 answer:
Therefore, the table of values used to create the scatterplot is Column 1 labelled Day of Fund Drive with entries 1, 2, 3, 4, and 5. Column 2 is labeled Money raised (dollars) with entries 200, 300, 200, 400, 300.
The given points are at (1, 200), (2, 300), (3, 200), (4, 400), (5, 300).
We need to find which table of values was used to create the scatterplot.
<h3>What is a scatterplot?</h3>A graph in which the values of two variables are plotted along two axes, the pattern of the resulting points revealing any correlation present.
Here, the graph x-axis represents the day of the fund drive and the y-axis represents money raised.
The ordered pairs are (1, 200), (2, 300), (3, 200), (4, 400), (5, 300).
The table to create a scatterplot is as follows:
Day of the fund drive Money raised ($)
1 200
2 300
3 200
4 400
5 300
Therefore, the table of values used to create the scatterplot is A 2-column table with 5 rows. Column 1 is labeled Day of Fund Drive with entries 1, 2, 3, 4, 5. Column 2 is labeled Money raised (dollars) with entries 200, 300, 200, 400, 300.
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Answer:
From five given points it is find that points (1 , 1) and (4 , -1) will apply
Step-by-step explanation:
According to question,
Slop of line (m) =
And y-intercept is ( 0, )
So from above slope and points, the equation of line can be written as
y = mx + c
i.e =
x + c
=
(0) + c
= 0 + c
Or, c =
A) With points ( 5, )
At x = 5, y = (5) +
or, y = +
so, y =
Hence this points do not apply
B) With points ( 1 , 1 )
At x = 1, y = (1) +
or, y =
So, y =
y = 1
Hence this points will apply
C) With points ( 4 , -1 )
At x = 4 , y = (4) +
y =
y =
So, y= -1
Hence this points will apply
D) With points (-3 ,7)
At x = - 3, y = (-3) +
y =
Hence this point will not apply
E) with points (0 , 0)
At x 0, y = (0) +
Or, y = 0 +
y =
Hence this point will not apply
∴ From above five given points it is find that points (1 , 1) and (4 , -1) apply
Answer
Answer:
She will need 41.22 meters.
Step-by-step explanation:
She knows that one leg of the triangle is 11 meters long and that the angle formed by that leg and the hypotenuse is 50 degrees .
The leg is adjacent to the hypothenuse. We know that the cosine of an angle is given by:
In which l is the length of the adjacent side and h is the hypothenuse.
Considering that we have , we can find the hypothenuse.
Looking at a calculator, the cosine of 50 degrees is 0.6428.
So
The other leg:
In a right triangle, with legs and
, and hypothenuse h, the pythagorean theorem states that:
We already have one of the legs and the hypothenuse, so:
How many meters will she need?
This is the perimeter of the garden, which is the sum of its dimensions, of 11 meters, 13.11 meters and 17.11 meters. So
She will need 41.22 meters.