Answer:
2) distance = 4 km
Displacement = 4 km east
3) distance = 35 km
Displacement = 5 km north
Step-by-step explanation:
2. He runs for 3 km in the east direction and then stops.. He now runs another 1 km in the same direction then stops.. Thus,
Total distance covered = 3 + 1 = 4 km
Total displacement is how far he is from his starting point = 3 + 1 = 4 km east
3) Runs 20km north and then runs 15 km back from starting point.
Thus;
Total distance covered = 20 + 15 = 35 km
Total displacement is distance from starting point = 20 - 15 = 5 km north
Subtracted because an opposite direction was taken after the 20km back to her starting point.
Answer:
thought i had it but answer is B......
The answer to the question
Answer:
.
Step-by-step explanation:
Answer:
318
Step-by-step explanation:
318 is the required answer
I hope it helped you
So given Figure we need to find total surface area
=Area(ABCD)+Area(BCRQ)+Area(QRSP)+Area(ADSP)+Area(ABQP)+Area(DCRS)
=(AB×BC)+(BC×CR)+(QR×RS)+(AD×DS)+(AB×BQ)+(DC×CR)
From figure,
AB=DC=PQ=SR=9 cm
BQ=CR=AP=DS=11 cm
BC=AD=QR=SP=3 cm
On substituting these values We get
Surface Area=(9×3)+(3×11)+(9×3)+(11×3)+(9×11)+(9×11)
=27+33+27+33+99+99=318
I hope it helped you
