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Kay [80]
3 years ago
6

James knows that when he walks, he takes about 120 steps per minute and that each step is 2.75 feet long. Which calculation is m

ost reasonable for James to use to find out his walking speed in miles per hour?
Mathematics
2 answers:
Inessa05 [86]3 years ago
4 0

Answer:

James can walk 3.75 miles per hour

Step-by-step explanation:

We can use conversion factors to determine the walking speed of James in miles per hour.

James takes 120 steps/minute with each step 2.75 feet long.

∴ If one step is equal to 2.75 feet then 120 steps per minute is:

= 2.75 (feet/step) × 120(steps/minute)

Where steps cancel out and you are left with:

= 330 feet/minute

1 Foot is equal to 0.00018939 miles. Therefore we can determined miles per hour as:

= (330 feet/minute) × (0.00018939miles/foot) × (60 minutes/1 hour)

Feet cancels out with the foot and minutes cancel out with minutes and you are left with:

= 3.75 miles/hour

mafiozo [28]3 years ago
3 0
Speed=120step/min=720step/h
Distance=720step/h×2.75feet/step=1980feet/h=0.375miles/h
So the answer is: he can walking 0.375miles per hour

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225 ft^2

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7 0
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Answer:

x>24

Step-by-step explanation:

Solve like a normal equation :)

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Note: Whenever dividing by a negative, you have to flip the sign of the inequality!

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6 0
3 years ago
In a clinical study, volunteers are tested for a gene that has been found to increase the risk for a disease. The probability th
MrRa [10]

Answer:

a) 0.984

b) 20 people

Step-by-step explanation:

a)

If The probability that a person carries the gene is 0.1, then in a sample of 20 people, 2 should carry the gene.

Now, we want to know how many samples there are with this property.

Since we have 20 elements where 18 are alike (do not carry the gene) and 2 are alike (carry the gene), we have to compute the number of permutations of 20 elements in which 18 are alike and 2 are alike. This number is

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(1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

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So there are 190-3 = 187 elements in which the first 3 elements have no 2 carriers, hence the probability that 4 or more people will have to be tested until 2 of them with the gene are detected is 187/190 = 0.984 (98.4%) rounded to three decimal places.

b)

Given that the probability that a person carries the gene is 0.1, then in a sample of 20 people, 20*0.1 = 2 should carry the gene.

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