2 years ago

Consider the equation 3p-7+p=13

Mathematics

1 answer:

GarryVolchara [31]2 years ago

3 0

Answer:

p=5

Step-by-step explanation:

3p-7+p=13

Add like terms.

3p+p-7=13

4p-7=13

Add 7 to both sides.

4p-7+7=13+7

4p=20

Divide 4 from both sides.

$\frac{4p}{4}$ = $\frac{20}{4}$

p=5

Hope this helps!

If not, I am sorry.

You might be interested in

How do I factor e^2-10e+25

olga nikolaevna [1]

Answer: (e-5)^2

Step-by-step explanation:

The box method is a good way to solve this, but for a quick explanation, start by finding a single value that when added gets -10 and when multiplied gets +25. We can find that this term is -5. We the can situate -5 into (e-5)^2 equation, where if you FOIL, you will be back at the unfactored equation. Hope this helps

7 0

3 years ago

Jacob is planting flowers for his grandmother. This morning, he spent an hour planting

kirill [66]

Answer:

Ignore my answer

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Write f(x) = 2x2 – 44x + 185 in vertex form.

forsale [732]

Answer:

Step-by-step explanation:

$f(x)=2x^2-44x+185\\\\=2(x^2-2*11*x)+185\\\\=2(x^2-2*11*x+11^2)+185-2*121\\\\\boxed{f(x)=2(x-11)^2-57}\\\\vertex\ is\ (11,-57)$

7 0

3 years ago

Read 2 more answers

Find three consecutive intgers whose sum is 171

Taya2010 [7]

$x,\ x+1,\ x+2\ \ - three\ consecutive\ integers\\\\Sum\ of\ those\ integers:\\\\x+x+1+x+2=171 \\\\3x=171-3\\\\3x=168\ \ \|:3\\\\x=56\\\\Three\ consecutive\ integers\ which\ sum\ is\
 171:\ 56,57,58.$

5 0

3 years ago

PLZZZ HELP 30 POINTSSS!!! Select the correct answer.

baherus [9]

Answer:

the answer is A

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers