66 2/3
=(66*3+2)/3
=200/3
((200/3)*39)/100
=(7800/117)/100
=78/1.17
=66.7%
not so sure it is right though, but that's what I came up with. hope it helps
Step-by-step explanation:
x + 8a = 25 + ax - 7a
x = 5
5 + 8a = 25 + 5a - 7a
5 + 8a = 25 - 2a
5 + 10a = 25
10a = 20
a = 2
Answer:
again, yes
Step-by-step explanation:
someone can help you, but not me
Answer:
0
Step-by-step explanation:
given that we roll a fair die repeatedly until we see the number four appear and then we stop.
the number 4 can appear either in I throw, or II throw or .... indefinitely
So X = the no of throws can be from 1 to infinity
This is a discrete distribution countable.
Sample space= {1,2,.....}
b) Prob ( 4 never appears) = Prob (any other number appears in all throws)
= 
where n is the number of throws
As n tends to infinity, this becomes 0 because 5/6 is less than 1.
Hence this probability is approximately 0
Or definitely 4 will appear atleast once.
Answer:
Step-by-step explanation: