Answer:
1 and 2
Step-by-step explanation:
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Answer:
D. One of the jellybeans that slipped out was orange and one was black
Step-by-step explanation:
We calculate the option with the highest probability of occurrence :
Total number of jellybean = 75
n(T) =75
n(Pink) = 8
n(red) = 22
n(Orange) = 17
n(green) = 8
n(white) = 6
n(black) = 4
We assume that the jelly beans must have slipped out one after the other.
Evaluating the options :
A.)
P(pink) and P(white)
8/75 * 6/74 = 0.0086486
B.)
P(green) and P(green)
8/75 * 7/74 = 0.0100900
C.)
P(white) and P(white)
6/75 * 5/74 = 0.0054054
D.)
P(orange) and P(black)
17/75 * 4/74 = 0.0122522
From the probability values obtained, the highest is D. Hence, the most likely to have occurred is One of the jellybeans that slipped out was orange and one was black
Answer:
Step-by-step explanation:
H0 : μ = 46300
H1 : μ > 46300
α = 0.05
df = n - 1 = 45 - 1 = 44
Critical value for a one tailed t-test(since population standard deviation is not given).
Tcritical = 1.30
The test statistic :(xbar - μ) ÷ (s/sqrt(n))
The test statistic, t= (47800-46300) ÷ (5600√45)
t = 1500
t = 1500 / 834.79871
t = 1.797
The decision region :
Reject H0: if t value > critical value
1. 797 > 1.30
Tvalue > critical value ; We reject H0
Hence, there is sufficient evidence to conclude that cost has increased.
Answer:
84.5
Step-by-step explanation:
(9.9 × 10) ÷ 2= 49.5 (7×10)÷2 = 35
35+49.5 = 84.5