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Viefleur [7K]
4 years ago
13

What equation do you use sum for the answer?

Mathematics
1 answer:
swat324 years ago
8 0

Answer:

fdsfdsferge21r324234

Step-by-step explanation:

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Point M is the midpoint of AB. AM = 3x+3, and AB = 8x-6. What is the length of AM?
PSYCHO15rus [73]
AM= 21 Units 
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6 0
4 years ago
Read 2 more answers
Need help<br><br> What’s the answer to number 2??
almond37 [142]

Answer:

F. 5(12)(7)

Step-by-step explanation:

V=L×W×H

V=7×5×12

=F. V=5(7)(12)

3 0
3 years ago
Luke order an extra large square pizza for all of his friends. The area of the pizza was 289cm². what is the perimeter of crust
AlekseyPX

Answer:

68 cm

Step-by-step explanation:

√289 = 17

each side is 17 cm

17 * 4 = 68 cm

3 0
4 years ago
What is the area of the rectangle? shoe your work! do not round anything until the very end and round your final answer to the t
weeeeeb [17]

Answer:

The area of the rectangle is 42 units^2

Step-by-step explanation:

we know that

The area of rectangle is equal to

A=LW

In this problem

AB=DC

BC=AD

see the attached figure with letters to better understand the problem

we have that

L=BC\\W=AB

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have the points

A(2,-1),B(5,2),C(12,-5),D(9,-8)

<em>Find out the distance BC</em>

we have

B(5,2),C(12,-5)

substitute in the formula

d=\sqrt{(-5-2)^{2}+(12-5)^{2}}

d=\sqrt{(-7)^{2}+(7)^{2}}

d_B_C=\sqrt{98}\ units

<em>Find out the distance AB</em>

we have

A(2,-1),B(5,2)

substitute in the formula

d=\sqrt{(2+1)^{2}+(5-2)^{2}}

d=\sqrt{(3)^{2}+(3)^{2}}

d_A_B=\sqrt{18}\ units

<em>Find out the area</em>

A=(L)(W)

we have

L=d_B_C=\sqrt{98}\ units

W=d_A_B=\sqrt{18}\ units

substitute

A=(\sqrt{98})(\sqrt{18})=42.0\ units^2

4 0
4 years ago
Carly needs $149 to buy a skateboard. She already has $52. She earns money washing cars for $20 a car.
Blababa [14]

Answer:

$149 - skateboard price

$52 - carly's money

$20 × 5 cars = $100

$100 + $52 = $152

$152 - $149 = $3 left

5 0
3 years ago
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