Leg 1 would be 120 ft, leg 2 would be 50 ft. use the formula a^2+b^2=c^2, a&b are legs, c is hypotenuse. sqt 16900= 130. (the issue with the question is the height of the person, but I think the question wants the hypotenuse.
The answer for the question is 21
Answer:
the daily fee =33 dollars
and the mileage charge.=0.35
Step-by-step explanation:
let d: be daily fee and m for mileage
cost of rental =(d*number of days)+ (m*number of mileage)
her first trip: 4d+440m=286
her second trip: 3d+190m=165.5
solve by addition and elimination
4d+440m=286 ⇒ multiply by 3 ⇒12d +1320m=(3)286
3d+190m=165.5⇒ multiply by 4⇒12d+190(4)m=4(165.5)
12d+1320m=858
12d+760m=662
subtract two equation to eliminate d
12d+1320m-12d-760m=858-662
560m=196
m=7/20=0.35 for on mileage
d: 4d+440m=286
4d=286-440(0.35)
d=(286-154)/4 33 dollars
Step = 9
a30 = a1 + 9(30 - 1) = -4 + 9 × 29 = -4 + 261 = 267