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solmaris [256]
3 years ago
15

Factor by grouping m(2a+b)-n(2a+b)+2n(2a+b)

Mathematics
1 answer:
lys-0071 [83]3 years ago
5 0

The factored expression of m(2a+b)-n(2a+b)+2n(2a+b) is (m + n)(2a + b)

<h3>How to factor the expression?</h3>

The expression is given as:

m(2a+b)-n(2a+b)+2n(2a+b)

Factor out 2a + b

m(2a+b)-n(2a+b)+2n(2a+b) = (m - n + 2n)(2a + b)

Evaluate the like terms

m(2a+b)-n(2a+b)+2n(2a+b) = (m + n)(2a + b)

Hence, the factored expression of m(2a+b)-n(2a+b)+2n(2a+b) is (m + n)(2a + b)

Read more about factored expressions at:

brainly.com/question/723406

#SPJ1

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Maxim and Salma were asked to find an explicit formula for the sequence 54,63,72,81,... Maxim said the formula is f(n)=54+9n Sal
Sever21 [200]

ANSWER

The explicit rule is

f(n) = 45+9n

EXPLANATION

The given sequence is :

54,63,72,81,...

The first term of this sequence is

a = 54

The common difference is

d =63 - 54 = 9

The explicit rule is given by:

f(n) = a + d(n - 1)f(n) = 54+9(n -1 )

We expand to get:

f(n) = 54+9n -9

f(n) = 45+9n

None of them is correct .

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4 years ago
If two angles of a triangle have measures of 42° and 20°, what is the measure of the third angle?
dexar [7]

The other angle would be 118°

The three angles of a triangle must add up to 180°.

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3 years ago
If i had 475 cannolis ans a box can only carry 15 how many boxes will i need.​
loris [4]

Answer:

you would need 32 boxes

Step-by-step explanation:

475/15 = 31.666

5 0
3 years ago
Read 2 more answers
Find the midpoint of the line segment joining the points (6,1) and (-2, -1).
tiny-mole [99]

Step-by-step explanation:

By the formula of slope, we have

( \frac{y  _{2}  - y_{1} }{x _2 - x _{1} }) \\ (  \frac{ - 1 - 1}{ - 2 - 6}  ) \\ ( \frac{ - 2}{ - 8} ) \\ (  \frac{1}{4} )

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Which of the following trigonometric inequalities has no solution over the interval 0 ≤ x ≤ 2pi radians?
valentinak56 [21]

Answer:

A .cos(x)<1

Step-by-step explanation:

According to the first inequality

cos(x)<1

x < arccos 1

x<0

This therefore does not have a solution within the range 0 ≤ x ≤ 2pi

x cannot be leas than 0. According to the range not value, 0≤x which is equivalent to x≥0. Thus means otvis either x = 0 or x> 0.

For the second option

.cos(x/2)<1

x/2< arccos1

x/2<0

x<0

This inequality also has solution within the range 0 ≤ x ≤ 2pi since 0 falls within the range of values.

For the inequality csc(x)<1

1/sin(x) < 1

1< sin(x)

sinx>1

x>arcsin1

x>90°

x>π/2

This inequality also has solution within the range 0 ≤ x ≤ 2pi since π/2 falls within the range of values

For the inequality csc(x/2)<1

1/sin(x/2) < 1

1< sin(x/2)

sin(x/2)> 1

x/2 > arcsin1

X/2 > 90°

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x>π

This value of x also has a solution within the range.

Therefore option A is the only inequality that does not have a solution with the range.

6 0
4 years ago
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