Answer:
![6t + \frac{t^2}{2}+2/5t^{5/2} + C](https://tex.z-dn.net/?f=6t%20%2B%20%5Cfrac%7Bt%5E2%7D%7B2%7D%2B2%2F5t%5E%7B5%2F2%7D%20%2B%20C)
Step-by-step explanation:
Given the expression;
g(t) = 6 + t + t²/√t
This can be rewritten as;
g(t) = 6 + t +t²/t^1/2
g(t) = 6 + t +t^{2-1/2}
g(t) = 6 + t +t^3/2
Integrate the result
![\int\limits {(6 + t+t^{3/2}}) \, dt\\](https://tex.z-dn.net/?f=%5Cint%5Climits%20%7B%286%20%2B%20t%2Bt%5E%7B3%2F2%7D%7D%29%20%5C%2C%20dt%5C%5C)
Using the formula x^{n+1}/n+1
![\int\limits {(6 + t+t^{3/2}}) \, dt\\ = 6t + \frac{t^2}{2}+\frac{t^{3/2+1}}{3/2 + 1} \\ = 6t + \frac{t^2}{2}+\frac{t^{5/2}}{5/2} \\= 6t + \frac{t^2}{2}+2/5t^{5/2} + C](https://tex.z-dn.net/?f=%5Cint%5Climits%20%7B%286%20%20%2B%20t%2Bt%5E%7B3%2F2%7D%7D%29%20%5C%2C%20dt%5C%5C%20%3D%206t%20%2B%20%5Cfrac%7Bt%5E2%7D%7B2%7D%2B%5Cfrac%7Bt%5E%7B3%2F2%2B1%7D%7D%7B3%2F2%20%2B%201%7D%20%5C%5C%20%3D%206t%20%2B%20%5Cfrac%7Bt%5E2%7D%7B2%7D%2B%5Cfrac%7Bt%5E%7B5%2F2%7D%7D%7B5%2F2%7D%20%5C%5C%3D%206t%20%2B%20%5Cfrac%7Bt%5E2%7D%7B2%7D%2B2%2F5t%5E%7B5%2F2%7D%20%2B%20C)
Answer:
sorry
Step-by-step explanation:
Answer:
The number of tile for which the cost is same route to nearest tile is 49 .
Step-by-step explanation:
Given as :
The cost which Joshua will pay for tile at one store = $ 0.99 per tile + $ 25 for tile saw
The cost which Joshua will pay for tile at another store = $ 1.50 per tile only
Let The number of tile for which the cost is same route to nearest tile = n
So, According to question
$ 0.99 × number of tile + $ 25 = $ 1.50 × number of tile
or, $ 0.99 × n + $ 25 = $ 1.50 × n
or, $ 1.50 × n - $ 0.99 × n = $ 25
I.e 0.51 × n = $ 25
∴ n = ![\frac{25}{0.51}](https://tex.z-dn.net/?f=%5Cfrac%7B25%7D%7B0.51%7D)
I.e n = 49.01 ≈ 49
So, The number of tile for which the cost is same route to nearest tile = n = 49
Hence The number of tile for which the cost is same route to nearest tile is 49 . Answer
Step-by-step explanation:
I=prt
I=7400×(26.5/100)×1
I=$1961
total money 7400+1962= $9361