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harkovskaia [24]
2 years ago
9

If 8 men on a construction crew make up 40% percent of the entire crew, how many people are in the crew?

Mathematics
2 answers:
asambeis [7]2 years ago
8 0
X(0.4)=8
x=8/0.4
x=20
so there’s 20 people in the crew
hope this helps !
pochemuha2 years ago
6 0

Answer:

Step-by-step explanation:

Since 40% of the crew are men, which means n. 40=8 n=8/. 40 n=20 total number of crew 20 - 8=12 are women

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Can someone please help.
zvonat [6]

Answer:

  • 8 jars

Step-by-step explanation:

Let the number of jars is x.

<u>80 liters distributed, each jar has:</u>

  • 80/x

<u>Redistribution with 4 less jars, each jar now has:</u>

  • 80/(x - 4)

<u>Each jar has now twice the amount:</u>

  • 80/x*2 = 80/(x - 4)
  • 2/x = 1/(x - 4)
  • 2(x - 4) = x
  • 2x - 8 = x
  • x = 8

She prepared 8 jars at the start

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3 years ago
HELP PLSS WILL GIVE BRAINLIEST!​
nydimaria [60]
15 i am pretty sure i’m probably gonna be wrong
3 0
3 years ago
Read 2 more answers
Write each of these in scientific notation <br> 1) 0.00000402<br> 2) 1,900,000
Mkey [24]

Answer:

See below in bold.

Step-by-step explanation:

1. 0.00000402

= 4.02 * 10^-6  (Counting the digits after the decimal point until we get to the 4 gives us the -6).

2.  1,900,000

= 1.9 * 10^6    ( counting the number of digits after the 1 gives us 6).

3 0
2 years ago
233.356 round to two significant figures
olchik [2.2K]
The answer is 230 :) 
6 0
3 years ago
Discrete Math
andrezito [222]

Answer:

Part c: Contained within the explanation

Part b: gcd(1200,560)=80

Part a: q=-6         r=1

Step-by-step explanation:

I will start with c and work my way up:

Part c:

Proof:

We want to shoe that bL=a+c for some integer L given:

bM=a for some integer M and bK=c for some integer K.

If a=bM and c=bK,

then a+c=bM+bK.

a+c=bM+bK

a+c=b(M+K) by factoring using distributive property

Now we have what we wanted to prove since integers are closed under addition.  M+K is an integer since M and K are integers.

So L=M+K in bL=a+c.

We have shown b|(a+c) given b|a and b|c.

//

Part b:

We are going to use Euclidean's Algorithm.

Start with bigger number and see how much smaller number goes into it:

1200=2(560)+80

560=80(7)

This implies the remainder before the remainder is 0 is the greatest common factor of 1200 and 560. So the greatest common factor of 1200 and 560 is 80.

Part a:

Find q and r such that:

-65=q(11)+r

We want to find q and r such that they satisfy the division algorithm.

r is suppose to be a positive integer less than 11.

So q=-6 gives:

-65=(-6)(11)+r

-65=-66+r

So r=1 since r=-65+66.

So q=-6 while r=1.

3 0
3 years ago
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