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BaLLatris [955]
2 years ago
14

There were 20 pumpkins in a garden. One fourth of the pumpkins were too small, one tenth were too large, and one half were just

the right size. The rest were not ripe yet. How many of the pumpkins were too small?
Mathematics
2 answers:
rosijanka [135]2 years ago
7 0

Answer:

5 pumpkins

Step-by-step explanation:

It is said that one fourth of the pumpkins is too small, so:

\frac{pumpkins-that-are-too-small}{total-amount-of-pumpkins}=\frac{1}{4}

This means one out of every four pumpkins is too small.

But we have a total of 20 pumpkins, not four, so we just need to multiply our real total amount of pumpkins with the ratio given and then we find the amount of pumpkins that are too small:

\frac{pumpkins-that-are-too-small}{total-amount-of-pumpkins}*total-amount-of-pumpkins

=pumpkins-that-are-too-small

So; filling in the numbers:

\frac{1}{4} *20 = \frac{1*20}{4}=\frac{20}{4}=5

Monica [59]2 years ago
5 0

Answer: 5 pumpkins

Step-by-step explanation:

      Since one-fourth of the pumpkins were too small, we will find one-fourth of 20 by dividing, then multiplying.

One fourth = \frac{1}{4} = 0.25

20 * 0.25 = 5

           5 pumpkins were too small.

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A 440.0-volt electric heater draws 10.0 amperes of current. according to Ohms law,what is the resistenace of the heater
Zanzabum

Answer:

The resistance of the heater is 44 ohms.

Step-by-step explanation:

Given that,

Voltage of electric heater, V = 440 volts

Current drawn by the heater, I = 10 A

We need to find the resistance of the heater. It is a case of Ohm's law. Its mathematical form is given by :

V=IR

R is resistance of the heater

R=\dfrac{V}{I}\\\\R=\dfrac{440\ V}{10\ A}\\\\R=44\ \Omega

So, the resistance of the heater is 44 ohms. Hence, this is the required solution.

4 0
3 years ago
Tell me which 4 letters are right! A? B? C? D? F? E? I WILL GIVE BRAINLIEST
Helen [10]

Answer:

Everything but A and C

Step-by-step explanation:

5 0
2 years ago
In a game called Taxation and Evasion, a player rolls a pair of dice. If, on any turn, the sum is 7, 11, or 12, the player gets
AnnZ [28]

Answer:

Probability = \frac{243}{1024}

Step-by-step explanation:

Given

Sum = \{7, 11, 12\}

Rolls = 5

Required

Probability of not getting audited

If a pair of dice is rolled, the following are the observations of the sum

Outcomes = 36

Sum\ of\ 7 = 6

Sum\ of\ 11 = 2

Sum\ of\ 12 = 1

So, in a single roll; The probability of getting audited is:

p= \frac{1 + 2 + 6}{36}

p= \frac{9}{36}

p= \frac{1}{4}

The probability of not getting audited in a single roll is:

q = 1 - p --- Complement rule

q = 1 - \frac{1}{4}

Take LCM

q = \frac{4 - 1}{4}

q = \frac{3}{4}

The probability of not getting audited in 5 rolls is:

Probability = q^5

Probability = (\frac{3}{4})^5

Probability = \frac{3^5}{4^5}

Probability = \frac{243}{1024}

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3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
zvonat [6]

The solutions are x=15, x=-8 and x=9

Explanation:

Part a: The equation is \frac{1}{3} (5x-9)=2(\frac{1}{3} x+6)

Let us find the value of x.

Multiply the terms within the bracket, we get,

\frac{5}{3} x-3=\frac{2}{3} x+12

Subtracting both sides by \frac{2}{3} x, we have,

\frac{3}{3} x-3=12

Adding both sides by 3,

x=15

Thus, the solution of the equation \frac{1}{3} (5x-9)=2(\frac{1}{3} x+6) is x=15

Part b: The equation is 4(3x+5)-3=9x-7

Multiply the terms within the bracket, we get,

12x+20-3=9x-7

Subtracting both sides by 9x, we have,

3x+17=-7

Subtracting both sides by 17,

3x=-24

Dividing both sides by 3, we have,

x=-8

Thus, the solution of the equation 4(3x+5)-3=9x-7 is x=-8

Part c: The equation is 5(x+7)-3(x-4)=7x+2

Multiply the terms within the bracket, we get,

5x+35-3x+12=7x+2

Adding the like terms, we have,

2x+47=7x+2

Subtracting both sides by 2 and 2x, we get,

45=5x

Dividing both sides by 5, we have,

x=9

Thus, the solution of the equation 5(x+7)-3(x-4)=7x+2 is x=9

8 0
4 years ago
There is a group of 5 seniors and 8 first year graduate students to fill the openings of local news reporters. Suppose that we p
bagirrra123 [75]

Answer:

\frac{(C_{8|2}) (C_{5|2} ) + (C_{8|3} )(C_{5|1} )+ C_{8|4}}{C_{13|4} }

Step-by-step explanation:

The total amount of students in the pool is 13.

1) Find the probability that at least 2 first year graduate students are among the chosen group.

The total amount of different ways to chose 4 students from a pool of 13 is C_{13|4}

The total amount of ways to choose at least 2 first year graduate students would be:

Ways of choose 2 first year students and 2 seniors + ways of choose 3 first year students and 1 senior + ways of choose 4 first year students. <u>(we are adding and not multiplying because it's "choose 2 first year OR 3 OR 4")</u>

Therefore, the probability would be:

\frac{(C_{8|2}) (C_{5|2} ) + (C_{8|3} )(C_{5|1} )+ C_{8|4}}{C_{13|4} }

8 0
3 years ago
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