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1 year ago

Find the values of m&n if x

Mathematics

1 answer:

Sever21 [200]1 year ago

6 0

The values of m and n from the given equation are 1/4 and -2

<h3>Polynomial functions</h3>

Given the polynomial function below

f(x) = mx^4+2x^3-3x^2+nx-4

If the zeros are 2 and -2, hence;

0 = 16m+16-12+2n-4
0 = 16m-16+12-2n-4

_______________
16m+2n = 0
16m - 2n = 8

Subtract

2n+2n = -8
4n = -8

n = -2

Substitute for "m'

16m + 2(-2) = 0
16m = 4

m = 1/4

Hence the values of m and n from the given equation are 1/4 and -2

Learn more on polynomials here; brainly.com/question/2833285

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Answer:

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3 years ago

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Pepsi [2]

Answer:

The error made is that the graph of $y=x^{2} +3$ is a vertical translation up by 3, instead of down.

Step-by-step explanation:

Exponential functions, when they are graphed, use the function $f(x)=a(x-h)^{2} +k$ .

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2 years ago

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mylen [45]

Answer:

The answer is D.

Step-by-step explanation:

Well since there are 4 values calculated then 2 would be above the mean because plus the 2 values above the mean. I don't know if it makes since though.

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2 years ago

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luda_lava [24]

Answer:

The required formula is:

$\ a_{n}=a_{1}+(n-1)d$

Step-by-step explanation:

The total number of squares of the the first term = 4

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so,

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$d=a_3-a_2=10-7=3$

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As the common difference 'd' is same, it means the sequence is in arithmetic.

If the initial term of an arithmetic progression is $a_{1}$ and the common difference of successive members is d, then the nth term of the sequence $(a_n)$ is given by:

$\ a_{n}=a_{1}+(n-1)d$

Therefore, the required formula is:

$\ a_{n}=a_{1}+(n-1)d$

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3 years ago

A student claims that the rectangular point below can be represented by the

Sladkaya [172]

Since we don't have a figure we'll assume one of them is right and we're just being asked to check if they're the same number. I like writing polar coordinates with a P in front to remind me.

It's surely false if that's really a 3π/7; I'll guess that's a typo that's really 3π/4.

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P(-6√2, 3π/4) = ( -6√2 cos 3π/4, -6√2 sin 3π/4 )

That's true since when we add pi to an angle it negates both the sine and the cosine,

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Answer: TRUE

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3 years ago