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uysha [10]
3 years ago
12

Y = 2x - 3 y = 2x + 1

Mathematics
1 answer:
ryzh [129]3 years ago
4 0

Answer:

No solution.

General Formulas and Concepts:

<u>Algebra I</u>

  • Solving systems of equations by graphing

Step-by-step explanation:

If the lines are parallel, they will have no solutions.

If the lines are the same, they will have infinite solutions.

If the lines are anything else, they will usually have 1 solution.

If we graph the systems of equations, we see that the lines are parallel.

∴ the systems has no solution.

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Is the relationship linear?
lianna [129]
Yes it is linear yes
5 0
3 years ago
The pen is 2 cm shorter than the scale. if the scale is 7 inches long. how long is the pen?
Makovka662 [10]

The pen is 15.78 centimeters long when scale is 7 inches long and pen is 2cm shorter then the scale.

How to find the how much long is the pen ?

Scale is 7 inches long and

We know that

7inches=17.78cm

And pen is 2cm shorten then the scale

So the length of the pen is

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=6.21 inches

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brainly.com/question/28048541

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2 years ago
Find all the solutions of the equation in the interval [0,2pi). 4sin^(2)x=5-4cosx
gulaghasi [49]
                       4sin²(x) = 5 - 4cos(x)
        4{¹/₂[1 - cos(2x)]} = 5 - 4cos(x)
   4{¹/₂[1] - ¹/₂[cos(2x)]} = 5 - 4cos(x)
         4[¹/₂ - ¹/₂cos(2x)] = 5 - 4cos(x)
     4[¹/₂] - 4[¹/₂cos(2x)] = 5 - 4cos(x)
                2 - 2cos(2x) = 5 - 4cos(x)
              - 2                   - 2
                    -2cos(2x) = 3 - 4cos(x)
            -2[2cos²(x) - 1] = 3 - 4cos(x)
               -4cos²(x) + 2 = 3 - 4cos(x)
                               - 2  - 2
                     -4cos²(x) = 1 - 4cos(x)
-4cos²(x) + 4cos(x) - 1 = 0
 4cos²(x) - 4cos(x) + 1 = 0
               [2cos(x) - 1]² = 0
                  2cos(x) - 1 = 0
                              + 1 + 1
                       2cos(x) = 1
                            2         2
                         cos(x) = ¹/₂
                cos⁻¹[cos(x)] = cos⁻¹(¹/₂)
                                 x = 60, 300
                                 x = π/3, 5π/3

[0, 2π) = 0 ≤ x < 2π
[0, 2π) = 0 ≤ π/3 ≤ 2π or 0 ≤ 5pi/3 < 2π
5 0
3 years ago
Solve the inequality
mojhsa [17]

Answer:

D

Step-by-step explanation:

4 0
3 years ago
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