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Olenka [21]
2 years ago
14

Find the slope of the curve y=2/x at x=a.​

Mathematics
1 answer:
Degger [83]2 years ago
6 0

Answer:

  • We are given:- y=2/x
  • We need to find the slope of the curve at x=a.

Step-by-step explanation:

Solution,

We use the slope formula, setting x=a :

\displaystyle{{{{ \lim_{h \to0}}}} \frac{ \frac{2}{x + h}  -  \frac{2}{x} }{h}  =   \lim_{h \to0}  \frac{ \frac{2}{a + h}  -  \frac{2}{a} }{h} }

\displaystyle{ \lim_{h \to0} \frac{ \frac{2a - 2(a + h)}{a(a + h)} }{h}  =  \displaystyle{ \lim_{h \to0} \frac{2a - 2(a + h)}{ha(a + h)}  }}

\displaystyle{ \lim_{h \to0} \frac{2a - 2a - 2h}{ha(a + h)}  =  \displaystyle{ \lim_{h \to0}  \frac{ - 2h}{ha(a + h)} }}

\displaystyle{ \lim_{h \to0}  \frac{ - 2}{a(a + h)}  =  -  \frac{  2}{ {a}^{2} } }

<em><u>T</u></em><em><u>h</u></em><em><u>e</u></em><em><u>r</u></em><em><u>e</u></em><em><u>f</u></em><em><u>o</u></em><em><u>r</u></em><em><u>e</u></em><em><u>,</u></em><em><u> </u></em><em><u>T</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>s</u></em><em><u>l</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>o</u></em><em><u>f</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>c</u></em><em><u>u</u></em><em><u>r</u></em><em><u>v</u></em><em><u>e</u></em><em><u> </u></em><em><u>y</u></em><em><u>=</u></em><em><u>2</u></em><em><u>/</u></em><em><u>x</u></em><em><u> </u></em><em><u>a</u></em><em><u>t</u></em><em><u> </u></em><em><u>x</u></em><em><u>=</u></em><em><u>a</u></em><em><u> </u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>-</u></em><em><u>2</u></em><em><u>/</u></em><em><u>a</u></em><em><u>^</u></em><em><u>2</u></em><em><u>.</u></em>

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If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that
Ivan

Answer:

\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

\sf\implies cos2A = 1 - 2sin^2A

Therefore , here substituting the value of sinA , we have ,

\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2

Simplify the whole square ,

\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}

Add the numbers in numerator ,

\sf\implies cos2A =  1-2\times \dfrac{4-2\sqrt3}{8}

Multiply it by 2 ,

\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}

Take out 2 common from the numerator ,

\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}

Simplify ,

\sf\implies cos2A =  1 -\dfrac{ 2-\sqrt3}{2}

Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

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An ice cream shop sells cones at the volume of 94.2 cubic meters they want to double the volume of the cones without changing th
marin [14]
The volume of a cone is V=\pi r^2\frac{h}3 where r = radius and h = height. If the cone has a volume of 94.2 cm³ (I assume you didn't mean m³ because that would be ridiculously huge) and a height of 10 cm, we can plug these values into the formula to find the radius. Don't do any rounding.

94.2 = \pi r^2\frac{10}3 \\ 282.6 = \pi r^2 *10 \\ 28.26 = \pi r^2 \\ 8.99543738355 = r^2 \\ 2.99923946752=r

Now we know that's going to be the radius of our <em>new </em>cone as well since we're keeping the diameter the same. The volume is going to be double 94.2 which is 188.4. Let's solve for the height.

188.4 = \pi (2.99923946752)^2\frac{h}3 \\ 188.4 = \pi(8.99543738355)\frac{h}3 \\ 188.4 = 28.26\frac{h}3 \\ 565.2 = 28.26h \\\\ \boxed{h = 20, r\approx 3}
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Ivan

Answer:

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Step-by-step explanation:

The marked price of item is $250.

Two successive discounts are 20% and 30%.

Price of item after discounts of 20% is

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New price of item after first discount is $200.

Price of item after second discount, i.e., 30% is

200-\frac{30}{100}(200)=200-60=140

Therefore, the price of item after successive discounts are 20% and 30% is $140.

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