We will get the number of possible selections, and then subtract the number less than 25 cents.
We can choose the number of dimes 5 ways 0,1,2,3 or 4.
We can choose the number of nickels 4 ways 0,1,2 or 3.
We can choose the number of quarters 3 ways 0,1, or 2.
That's 5*4*3 = 60 selections
Now we must subtract from the 60 the number of selections of coins that are less than 25 cents. These will involve only dimes and nickels.
To get a selection of coin worth less than 25 cents:
If we use no dimes, we can use 0,1,2 on all 3 nickels.
That's 4 selections less than 25 cents. (that includes the choice of No coins at all in the 60, which we must subtract).
If we use exactly 1 dime , we can use 0,1,2, or all 3 nickels.
That's the 3 combinations less than 25 cents.
And there is 1 other selection less than 25 cents, 2 dimes and no nickels.
So that's 4+3+1 = 8 selections which we must subtract from the 60.
Answer 60-8 = 52 selections of coins worth 25 cents or more.
Answer:
13421+402
Step-by-step explanation:
Answer: 12-5d
because all you do is flip the expression
Answer:
X = -2 and 4
Step-by-step explanation:
Move all of the terms to one side and set the equation to 0:
2x^2-14x+40-3x^2+16x-32 = 0
Then combine all like terms which would look like the following:
-x^2 + 2x + 8=0
Change the signs on both sides of the equation:
x^2 - 2x - 8 =0
Write -2x as a difference:
x^2 + 2x - 4x -8 = 0
Factor the expression:
x(x+2) x 4(x+2)=0
Factor out x+2 from the equation:
(x+2) (x-4)=0
Split into classes and then find the answer from there:
x+2=0
x-4=0
Answer:
6<0 is the right answer
Step-by-step explanation:
this is due to addition
