A lock consist of 4 dials where each dial has 6 letters what is the probability of guessing the right combination in one try’s
1 answer:
Using it's concept, it is found that the probability of guessing the right combination in one try’s is of .
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
In this problem, there are 4 dials, each with a probability of getting it correct, hence the probability of getting the right combination is given by:
.
More can be learned about probabilities at brainly.com/question/14398287
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(1, ) and (1, -
)
Step-by-step explanation:
Step 1 :
The co ordinates of the given equilateral triangle are A(-2,1) and B(4,1)
The distance between these 2 points is the length of the given triangle
Distance between the 2 points is = sqrt (sq(4-(-2)) + sq(1-1)) = 6
Hence the given triangle has 3 equal side of length 6 unit.
Step 2:
The length of the other side should be 6. Let (x,y) be the co-ordinate of the point C
We have then x = 1 (because the perpendicular from C to AB bisects AB we have the point C to have the x co-ordinate as 1)
Also we have the distance between the point B(4,1) and C(1,y) to be 6 as this is an equilateral triangle
Hence = 6
=> 9 + 1 + -2 y = 6
=> -2 y - 26 = 0
=> y = 2± sqrt(4+104) / 2 = 1 ± sqrt(27)
Hence the possible co ordinates of C are (1, ) and (1, -
)