Question

e) The allele for small size is recessive, and the allele for normal size is dominant. The frequency for the normal-size allele is 0.72. What percentage of the rats are normal sized? (3 points)

Answer 1

Answer:

51.84%

Explanation:

p² + 2pq + q² = 1 and p + q = 1

p = frequency of the dominant allele in the population

q = frequency of the recessive allele in the population

p²  = percentage of homozygous dominant individuals

q²  = percentage of homozygous recessive individuals

2pq = percentage of heterozygous individuals

p = 0.72 => p² = 0.72² = 0.5184

=> Percentage of the rats are normal sized: 51.84%