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mezya [45]
2 years ago
9

What is the range of the function f(x) = -2|x + 1|?

Mathematics
1 answer:
yanalaym [24]2 years ago
7 0

Answer:

obviously, it's at least -∞

since -2|x+1| can't be positive, we consider max(f(x)) as 0

so the range is

(-∞,0]

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Can someone help me? - will mark as best brain if you help me out (//^.^//)
wariber [46]

Answer:

1- Circumference: 43.96 Area: 153.86

2- Circumference: 69.08  Area: 379.94

3- Circumference: 40.82  Area: 132.67

4- Circumference: 28.26 Area: 63.59

5- Circumference: 57.78 Area: 265.77

3 0
2 years ago
Read 2 more answers
Help me please ?????????
exis [7]
The correct answer is:  [C]:  " $4290.00 " .
_______________________________________
Explanation:
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Given:  principal, "P":  equals:  $14,300  ;
                 rate, "r" : equals:  7.5 %  = 7.5 / 100 = 0.075 ; 
                time, "t" (in years): equals:  4  ;
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What is the interest, "i" ? 
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  Note:  The formula:  i = P * r * t   .
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So, we plug in our given values for "P", "r", and "t", and solve for "i" (interest).
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i = ($14,300) *(0.075) * (4)  ;

i = $1,490 ;  which is answer choice:  [C]:  " $4290.00 " .
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5 0
3 years ago
Find the quotient of 4/16743? (it's division)
sammy [17]

Answer:2.3 or 2.38

Step-by-step explanation:

I know

4 0
3 years ago
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Use the method of completing the square to transform the quadratic equation into the equation form (x + p)2 = q. 3 + x - 3x2 = 9
Triss [41]
To <span>transform the quadratic equation into the equation form (x + p)2 = q we shall proceed as follows:
3+x-3x^2=9
putting like terms together we have:
-3x^2+x=6
dividing through by -3 we get:
x^2-x/3=-2
but
c=(b/2a)^2
c=(-1/6)^2=1/36
thus the expression will be:
x^2-x/3+1/36=-2+1/36
1/36(6x-1)</span>²=-71/36

the answer is:
1/36(6x-1)²=-71/36
7 0
3 years ago
Triangle ABC is an isosceles triangle in which side
Shkiper50 [21]

Answer:

Option B.

Step-by-step explanation:

Consider the below figure attached with this question.

It is given that triangle ABC is an isosceles triangle.

From the below figure it is clear that the vertices of triangle are A(-2,-4), B(2,-1) and C(3,-4).

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using this formula, we get

AB=\sqrt{(2-(-2))^2+(-1-(-4))^2}=\sqrt{16+9}=5

BC=\sqrt{(3-2)^2+(-4-(-1))^2}=\sqrt{1+9}=\sqrt{10}

AC=\sqrt{(3-(-2))^2+(-4-(-4))^2}=\sqrt{25}=5

Now,

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So, perimeter of triangle ABC is 10+\sqrt{10} units.

Therefore, the correct option is B.

4 0
3 years ago
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