Okay.
Well, first of all you need to know what an x-intercept is.
It's the point of when the line crosses over the x-axis. For this, situation it crosses twice. An x-intercept written out is normally written out as (#, 0)
Out of that table you have two that apply to (#, 0)
(-6, 0) and (11,0)
the question is asking for a positive x-intercept. I'm guessing you know the difference. between negative and positive. but just in case, I'll use the number 5. As a positive: 5 As a negative: -5
So, you have -6 and 11.
the 6 is negative(-) the 11 is positive(+).
So your answer would be (11,0)
I hope this helped! :)
Answer:
D.
24
Step-by-step explanation:
good luck have a nice day
Answer:
Cot(theta) = - 0.75 or -3/4
Step-by-step explanation:
The hypotenuse is 5
The y value is 4
We need to find the corresponding x value.
x^2 + y^2 = z^2
X = ?
y = 4
z = 5
x^2 + 4^2 = 5^2
x^2 + 16 = 25
x^2 = 9
Now in this case, you are in quadrant 2, so the x value is - 3
sqrt(x^2) = sqrt(9)
x = - 3
The cot value is the adjacent (x value) / the opposite ( y ) value
Cot(theta) = -3/4
cot(theta) = -0.75
The answer is zero.
Explanation:
The 4 is in the ten-thousands place.
Write the number 47,283 with an additional zero in the 100,000 place.
047,283
To round to the nearest 100,000, all digits to the right of the 100,000 place become zero. That means that the digits 47283 all become zero. Since 4 is less than 5, the digit to its left is not raised by 1, so the 100,000 place digit remains zero, and you end up with 000,000, which is simply 0.
Answer: 0
