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juin [17]
2 years ago
15

The drama club is building a backdrop using arches whose shape can be represented by the function

Mathematics
1 answer:
ioda2 years ago
7 0

The length of each arch segment is 6ft.

<h3>What is a quadratic equation?</h3>

Quadratic equation is an algebraic equation with the highest power of its variable as 2.

Analysis:

The points at which the curve touches the floor, f(x) = 0

so, -x^{2} +2x + 8 = 0

-x^{2} +4x -2x +8 = 0

-x(x-4) -2(x-4) = 0

(-x-2)(x-4) = 0

x = -2 or 4

so length of segment along the floor of each arm, the distance from -2 to 4 on  a graph is 6 = 4--2 = 6 feet

In conclusion, the length of the segment along the floor of each arch is 6 feet

Learn more about quadratic equation: brainly.com/question/1214333

#SPJ1

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7-8\div4(3^2-1)=7-8\div4(9-1) \\  \\ =7-8\div4(8)=7-8\div32=7- \frac{1}{2} \\  \\ =6  \frac{1}{2} = \frac{13}{2}



Part 3

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Part 4

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Part 5

[(2-3)^2-5]\cdot4=[(-1)^2-5]\cdot4 \\  \\ =(1-5)\cdot4=-4\cdot4=-16



Part 6

12-11\cdot2+16\div8=12-22+2 \\  \\ =-8



Part 7

-5+1\cdot3-(7-2^3)=-5+3-(7-8) \\  \\ =-2-(-1)=-2+1=-1



Part 8

8+2\cdot3-14\div7=8+6-2 \\  \\ =12



Part 9

(8-2)^2+\frac{1}{4}[4-3(6-10)]=6^2+\frac{1}{4}[4-3(-4)] \\  \\ =36+\frac{1}{4}[4-(-12)]=36+\frac{1}{4}(4+12)=36+\frac{1}{4}(16) \\  \\ =36+4=40



Part 10

7+(2-3^2)\cdot5=7+(2-9)\cdot5 \\  \\ =7+(-7)\cdot5=7+(-35)=7-35 \\  \\ =-28



Part 11

3-2[2^3+(-1)^3]=3-2[8+(-1)] \\  \\ =3-2(8-1)=3-2(7)=3-14 \\  \\ -11



Part 12

18+6\div3(2^2+5)=18+6\div3(4+5) \\  \\ =18+6\div3(9)=18+6\div27=18+ \frac{2}{9} \\  \\  =18 \frac{2}{9}
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