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Lelechka [254]
2 years ago
6

A sampling distribution is a distribution of

Mathematics
1 answer:
Ann [662]2 years ago
8 0

Answer:

sample means

Step-by-step explanation:

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What is the relationship between the discriminant of a quadratic and its graph?
faltersainse [42]

Answer:

In a quadratic equation of the shape:

y = a*x^2 + b*x + c

we hate that the discriminant is equal to:

D =  b^2 - 4*a*c

This thing appears in the Bhaskara's formula for the roots of the quadratic equation:

x = \frac{-b +-\sqrt{b^2 - 4ac} }{2a}

You can see that the determinant is inside a square root, this means that if D is smaller than zero we will have imaginary roots (the graph never touches the x-axis)

If D = 0, the square root term dissapear, and this implies that both roots of the equation are the same, this means that the graph touches the x axis in only one point, wich coincides with the minimum/maximum of the graph)

If D > 0 we have two different roots, so the graph touches the x-axis in two different points.

4 0
3 years ago
Find the length of the hypotenuse of an isosceles right triangle whose legs are 1 unit in length.
Kobotan [32]
h =  \sqrt{ 1^{2} + 1^{2} } = \sqrt{1+1} = \sqrt{2}
7 0
3 years ago
What is the solution set to <br> 4x – 8 = 9x + 2
Sveta_85 [38]
4x-8=9x+2
4x=9x+10
-5x=10
5x=-10
x=-2
6 0
3 years ago
Read 2 more answers
Find the truth set of each predicate.
Sedbober [7]

The truth set for each predicate are:

a) d ∈ { -6, -3, -2, -1, 1, 2, 3, 6}

b) d ∈ {  1, 2, 3, 6}

c) x ∈ { [-2, -1] U [1, 2]}

d) x ∈ {-2, -1, 1, 2}

<h3>How to find the truth set of each predicate?</h3>

We only need to find the sets of values such that the statements are true.

a)

We want to find vales of d, such that d is an integer, and 6/d is an integer.

Here the possible values of d will be:

d ∈ { -6, -3, -2, -1, 1, 2, 3, 6}

Which are all the factors of 6, so all these integers divide 6.

b) Same as before, but this time the domain is a positive integer, so now the truth set will be:

d ∈ {  1, 2, 3, 6}

c) We want to find real values of x such that:

1 ≤ x² ≤ 4

If we apply the square root to the 3 sides, we get two inequalities:

-√1 ≥ x ≥ -√4

√1 ≤ x ≤ √4

Simplifying:

-1  ≥ x ≥ -2

1  ≤ x ≤ 2

So the truth set is:

x ∈ { [-2, -1] U [1, 2]}

c) Same as before, but now we only have integer solutions, so the truth set is:

x ∈ {-2, -1, 1, 2}

If you want to learn more about predicates:

brainly.com/question/18152046

#SPJ1

5 0
2 years ago
Harvey is working on a weekly budget. He earns $459 per week. Harvey spends $200 per week on rent and utilities plus $85 per wee
sattari [20]

Step-by-step explanation:

i need help with this question

6 0
3 years ago
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