If 4x = 8x - 1 then 4x must be equivalent to 1. So that means x is .25 or 1/4.
Hope this helps!
(I assumed your trying to solve for x, please word the question better next time)
Make a change of coordinates:


The Jacobian for this transformation is

and has a determinant of

Note that we need to use the Jacobian in the other direction; that is, we've computed

but we need the Jacobian determinant for the reverse transformation (from

to

. To do this, notice that

we need to take the reciprocal of the Jacobian above.
The integral then changes to

Answer:
C) As x approaches positive infinity, f(x) approaches positive infinity
Step-by-step explanation:
- The domain is NOT all real numbers as x is either smaller than or bigger than 0, and smaller than or bigger than 2. So x ≠ 0 and x ≠ 2.
- This implies that there are asymptotes at x=0 and x=2.
Therefore, the function is NOT continuous.
- The function is NOT increasing over its entire domain as
f(x) = -x² -4x + 1 is decreasing for its given domain of 0<x<2
More information is required to answer the question correctly.