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2 years ago

What is the range of ƒ(x) = |x|? (–∞, 0) (–∞, ∞) (0, ∞) [0, ∞)

Mathematics

1 answer:

larisa86 [58]2 years ago

6 0

The range of the function f(x) = |x| is [0,∞)

<h3>How to determine the range?</h3>

The function is given as:

f(x) = |x|

The above is the parent equation of an absolute value function.

The above function cannot output any negative value.

This means that:

ƒ(x) >= 0

As an interval notation, we have:

[0,∞)

Hence, the range of the function f(x) = |x| is [0,∞)

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Please help! provide thorough explanation and use elimination method!!

ICE Princess25 [194]

Multiply both sides of the second equation by 100 to get rid of the decimals:

0.05n + 0.10d = 1.50

==> 5n + 10d = 150

Multiply both sides of the first equation by -5:

n + d = 21

==> -5n - 5d = -105

Add the two equations together:

(5n + 10d) + (-5n - 5d) = 150 + (-105)

Notice that the terms containing n get eliminated and we can solve for d :

(5n - 5n) + (10d - 5d) = 150 - 105

5d = 45

d = 45/5 = 9

Plug this into either original equation to solve for n. Doing this with the first equation is easiest:

n + 9 = 21

n = 21 - 9 = 12

So Donna used 12 nickels and 9 dimes.

8 0

3 years ago

How do I do this ?????

AleksAgata [21]

Answer:

y=3

Step-by-step explanation:

it says that y is the inverse of x so if x=3 and y=8, so if x=8 than y must equal 3

3 0

3 years ago

Read 2 more answers

A pair of pant and a t-shirt cost $25. If the pant cost $7.28 more than the shirt, how much did the pant cost?

Lena [83]

$16.14 =pants

Explanation:

$25-$7.28=17.72

17.72/2 =8.86

8.86+7.28=16.14

25-16.14=8.86 shirt

I hope that helped ..

4 0

3 years ago

Read 2 more answers

-2x-y=-5 In slope intercept form please! :)

schepotkina [342]

Answer:

-2x - y = -5 in slop intercept form would be y = -2x + 5

Step-by-step explanation:

-2x - y = -5

first add -2x to the left side to move it to the right side because whatever you do to one side u do to the other.

-y = -5 + 2x

divide by -1 on the whole equation

y = -2x + 5 is your answer.

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3 years ago

Can somebody prove this mathmatical induction?

Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

$\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2$

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

3 step:

Check for n=k+1 whether the statement

$\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)$

is true.

Start with the left side:

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)$

According to the 2nd step,

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

Substitute it into the $\ast$

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)$

So, you have proved the initial statement

4 0

4 years ago