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Lapatulllka [165]
3 years ago
14

The surface area of a cube is 96 square inches. What is the length of an edge of the cube, in inches?

Mathematics
2 answers:
Bezzdna [24]3 years ago
7 0

Answer:

16 inches

Step-by-step explanation:

A cube has 6 sides and to find the surface area you would multiply one side by 6, or add the six sides together. So instead, to find the length of one side, you divide the surface area, 96, by 6 to get 16.

Hope this helps you :)

9966 [12]3 years ago
6 0

Answer:

Step-by-step explanation:

let x be the length of cube=x in

surface area=6 x²

6 x²=96

x²=96/6=16

x=√16=4 in

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Hi- I need help please to get my HS diploma...did not graduate :(
andrew-mc [135]

The remainder from the division of the algebraic equation is -53/8.

<h3>What is the remainder of the algebraic expression?</h3>

The remainder of the algebraic expression can be determined by using the long division method.

Given that:
\mathbf{f(x) = \dfrac{x^3 - 6x^2 + 3x - 1}{2x-3}}

where:

  • The divisor = 2x -3

Using the long division method, we have:

\mathbf{= \dfrac{x^2}{2} +\dfrac{-\dfrac{9x^2}{2}+3x -1 }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} +\dfrac{-\dfrac{-15x}{4}-1 }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}+\dfrac{-\dfrac{53}{8} }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}-\dfrac{53 }{8(2x-3)}}

Therefore, we can conclude that the remainder is -53/8.

Learn more about the division of algebraic equations here:

brainly.com/question/4541471

#SPJ1

8 0
2 years ago
Help please!
bagirrra123 [75]

(d):  y = mx+n

m = -2/3 ⇒ y = (-2/3)x +n

A(-4,  6) ∈ d  ⇒ 6 = (-2/3)·(-4) +n ⇒ 6 = 8/3 +n ⇒

⇒ n = 6 - 8/3 ⇒ n = 10/3

Now, we have:

y = (-2/3)x +10/3


6 0
4 years ago
The weight of an object on the moon is of its weight on Earth. Write 1/6 as a decimal.​
xxTIMURxx [149]

Answer:

1/6 as an decimal would be, 0.1666 Continued

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A factory made 4250
vodomira [7]

Step-by-step explanation:

Total amount of cookies = 4250

butter cookies, b

Almond cookies, a

Chocolate cookies, c

It made 715 more butter cookies than

almond cookies

b = a + 715

It made 5 times as many chocolate cookies as almond

5a = c

Total amount of cookies

= a + b + c

= a + (a+715) + (5a)

= 7a + 715

7a + 715 = 4250

7a = 4250-715

a = 3535 / 7

a = 505

c = 5a

= 5 (505)

= 2525

The factory make 2525 chocolate cookies.

5 0
3 years ago
3. The adult men of the Dinaric Alps have the highest average height of all regions. The
ahrayia [7]

Using the normal distribution, it is found that:

  • 3 - a) The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.
  • 3 - b) The minimum height of man in the Dinaric Alps that would place  him in the top 10% of all heights is of 76.84 inches.
  • 4 - a) The 25th percentile for the math scores was of 71.6 inches.
  • 4 - b) The 75th percentile for the math scores was of 78.4 inches.

<h3>Normal Probability Distribution </h3>

In a <em>normal distribution </em>with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

Question 3:

  • The mean is of 73 inches, hence \mu = 73.
  • The standard deviation is of 3 inches, hence \sigma = 3.

Item a:

The 40th percentile is X when Z has a p-value of 0.4, so <u>X when Z = -0.253</u>.

Z = \frac{X - \mu}{\sigma}

-0.253 = \frac{X - 73}{3}

X - 73 = -0.253(3)

X = 72.2

The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

Item b:

The minimum height is the 100 - 10 = 90th percentile is X when Z has a p-value of 0.9, so <u>X when Z = 1.28</u>.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 73}{3}

X - 73 = 1.28(3)

X = 76.84

The minimum height of man in the Dinaric Alps that would place  him in the top 10% of all heights is of 76.84 inches.

Question 4:

  • The mean score is of 75, hence \mu = 75.
  • The standard deviation is of 5, hence \sigma = 5.

Item a:

The 25th percentile is X when Z has a p-value of 0.25, so <u>X when Z = -0.675</u>.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 75}{5}

X - 75 = -0.675(5)

X = 71.6

The 25th percentile for the math scores was of 71.6 inches.

Item b:

The 75th percentile is X when Z has a p-value of 0.25, so <u>X when Z = 0.675</u>.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 75}{5}

X - 75 = 0.675(5)

X = 78.4

The 75th percentile for the math scores was of 78.4 inches.

To learn more about the normal distribution, you can take a look at brainly.com/question/24663213

5 0
2 years ago
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