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uranmaximum [27]
2 years ago
8

Given the following exponential function, identify whether the change represents growth or decay, and determine the percentage r

ate of increase or decrease.
y=290(0.31)^x
Mathematics
1 answer:
NISA [10]2 years ago
7 0

The <em>exponential</em> function y = 290 · 0.31ˣ reports a decay as its <em>growth</em> rate is less than 1 and greater than 0. Its <em>percentage</em> rate of decrease is equal to 69 %.

<h3>How to determine the behavior of an exponential function</h3>

<em>Exponential</em> functions are <em>trascendental</em> functions, these are, functions that cannot be described <em>algebraically</em>. The <em>simplest</em> form of <em>exponential</em> functions is shown below:

y = a · bˣ     (1)

Where:

  • a - Initial value
  • b - Growth rate
  • x - Independent variable.
  • y - Dependent variable.

Please notice that this kind of <em>exponential</em> function reports a <em>growth</em> for b > 1 and <em>decay</em> for b < 1 and b > 0. According to the statement we have the function y = 290 · 0.31ˣ, then we conclude that the exponential function given reports a <em>decay</em>.

The <em>percentage</em> rate of decrease is determined by the following formula:

100 × (1-0.31) = 100 × 0.69 = 69 %

The <em>percentage</em> rate of decrease related to the <em>exponential</em> function is 69 %.

To learn more on exponential functions: brainly.com/question/11487261

#SPJ1

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Answer:

s^2_p = \frac{9*0.3^2 +9*0.4^2}{10+10-2}=0.125

s_p =\sqrt{0.125}=0.354

(2.7 -2.4) - 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=-0.032  

(2.7 -2.4)+ 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=0.632  

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data given

\bar X_M = 2.7 represent the sample mean for men

\bar X_F = 2.4 represent the sample mean for women

s_M = 0.3 represent the sample deviation for men

s_F = 0.4 represent the sample deviation for women

n_M = 10 sample size of male

n_F =10 sample size of women

The confidence interval is given by:

(\bar X_M -\bar X_F) \pm t_{\alpha/2} S_p \sqrt{\frac{1}{n_M}+\frac{1}{n_F}}   (1)

The polled variance can be calculated with this formula:

s^2_p = \frac{9*0.3^2 +9*0.4^2}{10+10-2}=0.125

s_p =\sqrt{0.125}=0.354

For a confidence of 95% the value for the significance is \alpha=1-0.95=0.05 and \alpha/2 = 0.025, the degrees of freedom are given by:

df = n_M + n_F -2= 10+10-2=18

And the critical value can be calculated with the following formula in excel: "=T.INV(1-0.025,18)" and we got t_{\alpha/2}=2.1

Now we can replace into the confidence interval:

(2.7 -2.4) - 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=-0.032  

(2.7 -2.4)+ 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=0.632  

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The difference of two cubes is factored by
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In this case it would be

C) 
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