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2 years ago

Diberi 1 ½s = ⅗t² + ⅓u², hitung (ii) nilai t apabila u = -6 dan s = 28

Mathematics

1 answer:

Vinil7 [7]2 years ago

7 0

Answer:

√2' = t

Step-by-step explanation:

1 1/2s = 3/5t^2 + 1/3u^2; substitute known values

1 1/2 • 28 = 3/5 • t^2 + 1/3 • -6^2; simplify

42 = 3 • t^2 ÷ 5 + 1/3 • 36

42 = 3 • t^2 ÷ 5 + 12; apply property of subtraction of equality

42 – 12 = 3t^2 ÷ 5 + 12 – 12; simplify

30 = 3t^2 ÷ 5; apply property of multiplication of equality

30 • 5 = 3t^2 ÷ 5 • 5; simplify

6 = 3t^2; apply property of division of equality

6 ÷ 3 = 3t^2 ÷ 3; simplify

2 = t^2

√2' = t

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2. Use property

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Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

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4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

Answer: correct option is B.

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4 years ago

Diberi 1 ½s = ⅗t² + ⅓u², hitung (ii) nilai t apabila u = -6 dan s = 28​

Diberi 1 ½s = ⅗t² + ⅓u², hitung (ii) nilai t apabila u = -6 dan s = 28