Answer:
The average value of over the interval is .
Step-by-step explanation:
Let suppose that function is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of over the interval by algebraic handling:
The average value of over the interval is .
<span />x=base price
x/10=major options package
x/50=destination charge
x+x/10+x/50=24,416
x=21,800
Answer:
Step-by-step explanation:
This is because we subtract 456 from each side.
We then divide the whole equation by <em>x</em> .
Adding 50 to both sides gives us <em>x</em> by itself, hope this helps :D
Rounding 2.199. The tenths digit is 1, which is 4 or less, so you will round down. Re-write 2.199 without the decimal places: 2 . So 2.199 rounds to 2.
Answer:
Table 3
Step-by-step explanation:
Check table three;
Since the left hand limit is not equal to the right hand limit , the limit as x approaches to 2 does not exist.
Therefore "nonexistent" is true, and table 3 is the correct model of the limits of the function at x = 2