4 times table: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40
5 times table: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50
6 times table: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60
7 times table: 7, 14, 21, 28, 35, 42, 49, 56, 63, 70
10 times table: 10, 20, 30, 40, 50, 60, 70, 80, 90, 100
Answer:
hold on might have to ask my teacher
Step-by-step explanation:
1. No answer ( may be due to incorrect question)
2. x = -3
y = 4
3. x= 4
y = 2
4.x = -63/40
y= -19/20
Step 1
Multiply equation 1 by the coefficient of x in equation 2
Multiply equation 2 by the coefficient of x I'm equation 1
(after completing this step you will derive equation 3 and 4 )
Step 2
Subtract equation 4 from equation 3
Step 3
Divide both sides of the equation by the coefficient of y
Step 4
substitute your value for y in equation 1 or 2
(after this you will derive the values of x)
Note : This method is for the Elimination of x
I hope it helps
3.15 will be your answer i am very sure of that
<span> 3(x+2y)+5x−y+1
Use distributive property
3x+6y+5x-y+1
Add 5x to 3x
8x+6y-y+1
Subtract y from 6y
Final Answer: 8x+5y+1</span>