Rewrite each of the following expressions without using absolute value: |x-5|+|x+5| if x<-5

0.66666667 as a fraction

Ierofanga [76]

Answer:

__________________________________________

The correct answer is: " $\frac{2}{3}$ " .

__________________________________________

Note: Let's assume that this given decimal value is really:

"0.66666666666666666....." ;

(non-terminating; but repeating the singing digit, "7" ; yet rounded to:

" 0.66666667 " ;

then: " 0.666... " = $\frac{666}{999}$ ;

= (666 ÷ 111) / (999 ÷ 111) ;

= 6/9 ;

= (6÷3)/(9÷3) ;

= 2/3 ;

= " $\frac{2}{3}$ "

→ which is our answer.

____________________________________________

Or: " 0.6666... " = 666 ÷ 999 = ? ;

using calculator :

= 0.66666667 ;

→ which is the "rounded off" number of "0.6666..." ;

— (infinitely repeating) ;

→ So 666 ÷ 999 =

→ " $\frac{666}{999}$ " ;

= " $\frac{2}{3}$ " ;

→ Either use a "fraction calculator" ;

or simplify as aforementioned.

____________________________________________

Hope this answer is helpful to you!

Best wishes to you in your academic pursuits

— and within the "Brainly" community!

____________________________________________

7 0

3 years ago

Read 2 more answers

Please help last one today

murzikaleks [220]

7 28/30 is the answer

4 0

3 years ago

Read 2 more answers

Help please!!! I really need it

jenyasd209 [6]

Answer:

140

Step-by-step explanation:

2000 divided by 7% will give you 140 hope it helps

6 0

3 years ago

Where should a fourth point be located to form a square?

Rina8888 [55]

The answer is (3,-4) because it machtes up with (-5,-4) and (3,4), so it (3,-4) is correct.

3 0

3 years ago

Read 2 more answers

A company manufactures and sells x television sets per month. The monthly cost and price-demand equations are C(x)equals72 com

solmaris [256]

Answer:

Part (A)

1. Maximum revenue: $450,000

Part (B)

2. Maximum protit: $192,500

3. Production level: 2,300 television sets

4. Price: $185 per television set

Part (C)

5. Number of sets: 2,260 television sets.

6. Maximum profit: $183,800

7. Price: $187 per television set.

Explanation:

0. Write the monthly cost and price-demand equations correctly:

Cost:

$C(x)=72,000+70x$

Price-demand:

$p(x)=300-\dfrac{x}{20}$

Domain:

$0\leq x\leq 6000$

1. Part (A) Find the maximum revenue

Revenue = price × quantity

Revenue = R(x)

$R(x)=\bigg(300-\dfrac{x}{20}\bigg)\cdot x$

Simplify

$R(x)=300x-\dfrac{x^2}{20}$

A local maximum (or minimum) is reached when the first derivative, R'(x), equals 0.

$R'(x)=300-\dfrac{x}{10}$

Solve for R'(x)=0

$300-\dfrac{x}{10}=0$

$3000-x=0\\\\x=3000$

Is this a maximum or a minimum? Since the coefficient of the quadratic term of R(x) is negative, it is a parabola that opens downward, meaning that its vertex is a maximum.

Hence, the maximum revenue is obtained when the production level is 3,000 units.

And it is calculated by subsituting x = 3,000 in the equation for R(x):

R(3,000) = 300(3,000) - (3000)² / 20 = $450,000

Hence, the maximum revenue is $450,000

2. Part (B) Find the maximum profit, the production level that will realize the maximum profit, and the price the company should charge for each television set. 

i) Profit(x) = Revenue(x) - Cost(x)

Profit (x) = R(x) - C(x)

$Profit(x)=300x-\dfrac{x^2}{20}-\big(72,000+70x\big)$

$Profit(x)=230x-\dfrac{x^2}{20}-72,000\\\\\\Profit(x)=-\dfrac{x^2}{20}+230x-72,000$

ii) Find the first derivative and equal to 0 (it will be a maximum because the quadratic function is a parabola that opens downward)

Profit' (x) = -x/10 + 230

-x/10 + 230 = 0

-x + 2,300 = 0

x = 2,300

Thus, the production level that will realize the maximum profit is 2,300 units.

iii) Find the maximum profit.

You must substitute x = 2,300 into the equation for the profit:

Profit(2,300) = - (2,300)²/20 + 230(2,300) - 72,000 = 192,500

Hence, the maximum profit is $192,500

iv) Find the price the company should charge for each television set:

Use the price-demand equation:

p(x) = 300 - x/20

p(2,300) = 300 - 2,300 / 20

p(2,300) = 185

Therefore, the company should charge a price os $185 for every television set.

3. Part (C) If the government decides to tax the company $4 for each set it produces, how many sets should the company manufacture each month to maximize its profit? What is the maximum profit? What should the company charge for each set?

i) Now you must subtract the $4 tax for each television set, this is 4x from the profit equation.

The new profit equation will be:

Profit(x) = -x² / 20 + 230x - 4x - 72,000

Profit(x) = -x² / 20 + 226x - 72,000

ii) Find the first derivative and make it equal to 0:

Profit'(x) = -x/10 + 226 = 0

-x/10 + 226 = 0

-x + 2,260 = 0

x = 2,260

Then, the new maximum profit is reached when the production level is 2,260 units.

iii) Find the maximum profit by substituting x = 2,260 into the profit equation:

Profit (2,260) = -(2,260)² / 20 + 226(2,260) - 72,000

Profit (2,260) = 183,800

Hence, the maximum profit, if the government decides to tax the company $4 for each set it produces would be $183,800

iv) Find the price the company should charge for each set.

Substitute the number of units, 2,260, into the equation for the price:

p(2,260) = 300 - 2,260/20

p(2,260) = 187.

That is, the company should charge $187 per television set.

7 0

3 years ago