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kirill115 [55]
3 years ago
5

Can someone tell me how to do this problem? (Steps)

Mathematics
1 answer:
bearhunter [10]3 years ago
3 0
<h2><u>Answer:</u></h2><h2 /><h2><u>➧</u><u>x>0</u><u> </u><u>&</u><u> </u><u>x</u><u><</u><u>-8</u></h2>

<u>Steps:</u>

➧9-∣x+4∣<5

Add -9 to both sides

➧9-∣x+4∣-9<5-9

➧-∣x+4∣<-4

Replace x+4 by X ☆☆

➧-∣X∣<-4

<u>☆</u><u>☆</u><u>Note:</u>

1)∣X∣ = -X if X is negative or <0

2)∣X∣ = X if X is positive or >0

<u>1) </u><u>If</u><u> </u><u>X</u><u> </u><u>is</u><u> </u><u>negative</u><u> </u><u>no</u>

➧-(-X)<-4

➧X<-4

➧x+4<-4

Add -4 to both sides

➧x+4-4<-4-4

<h2><u>➧</u><u>x<-8</u></h2>

<u>2) </u><u>I</u><u>f</u><u> </u><u> X</u><u> </u><u>is</u><u> </u><u>positive</u><u> </u><u>no</u>

➧-(X)<-4

➧-X<-4

➧-(x+4)<-4

➧-x-4<-4

Add 4 to both sides

➧-x-4+4<-4+4

➧-x<0

Multiply both side by -1 ☆☆☆

<h2><u>➧</u><u>x>0</u></h2>

☆☆☆

Multiplying both sides by a negative no changes > to < and vice versa

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Let's carry this math sentence over to its natural, "shapey" element. We're going to look at each term not as an ordinary number, but as <em>the area of some shape</em>.

x² (read as "x <em>squared"</em>) can be seen as the area of a square with side lengths of x. 2x can similarly be seen as the area of a <em>rectangle </em>with a length of x and a width of 2. (Picture 1)

What's our question actually asking, though? Something about <em>perfect squares</em>. More specifically, we're looking for something to add on that'll <em>make this thing a perfect square</em>. We're trying to find a missing piece we can slot in to make a square, in other words. Problem is, our shapes don't look much like a square if we put them together right now. We need to do a little cutting and gluing first.

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