2 years ago

A system of equations is shown below,

1 answer:

Vikki [24]2 years ago

4 0

Answer: No solution
Step by step:
10x-2(5x+2)=12
10x-10x-4=12
0x=16
No solution

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murzikaleks [220]

$y=4x^2-64=4(x^2-16)=4(x^2-4^2)=4(x-4)(x+4)\\\\-------------------------------\\\\4(x-4)(x+4)=0\iff x-4=0\ or\ x+4=0\\\\x=4\ or\ x=-4$

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Step-by-step explanation:

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