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NeX [460]
2 years ago
14

Simplify \root(3)(8x^(6))y^(12)

Mathematics
1 answer:
ExtremeBDS [4]2 years ago
4 0

The simplification form of the provided expression is 2x²y⁴ option first is correct.

<h3>What is an expression?</h3>

It is defined as the combination of constants and variables with mathematical operators.

We have an expression:

= \rm \sqrt[3]{8x^6y^{12}}

\rm =\sqrt[3]{8}\sqrt[3]{x^6}\sqrt[3]{y^{12}}

\rm \rm = \rm 2\sqrt[3]{x^6}\sqrt[3]{y^{12}}

\rm =2x^2\sqrt[3]{y^{12}}

\rm =2x^2y^4

Thus, the simplification form of the provided expression is 2x²y⁴ option first is correct.

Learn more about the expression here:

brainly.com/question/14083225

#SPJ1

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WILL GIVE BRAINLIEST, THANKS, AND 5 STARS!<br> PLEASE HELP ME!
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Answer:

-4 and 4

Step-by-step explanation:

<u>Method 1</u>

Apply Difference of Two Squares Formula: a^2-b^2=(a+b)(a-b)

Given  x^2-16=0

Rewrite 16 as 4²

Therefore, a^2=x^2 and b^2=4^2

\implies a = \sqrt{x^2}=x

\implies b=\sqrt{4^2} =4

\implies x^2-16^2=(x+4)(x-4)

\implies (x+4)(x-4)=0

\implies (x+4)=0 \implies x=-4

\implies (x-4)=0 \implies x=4

<u>Method 2</u>

Given equation:

x^2-16=0

Add 16 to both sides:

\implies x^2-16+16=0 + 16

\implies x^2=16

Square root both sides:

\implies \sqrt{x^2}=\sqrt{16}

\implies x=\pm4

Therefore, x = -4, x = 4

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Answer:

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Step-by-step explanation:

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Answer:

1) x = 17,  line a parallel to line b

2) x = 18,  line a parallel to line b

Step-by-step explanation:

If line a parallel to line b then (10x - 40) + 50 = 180

Solve for x

10x - 40 + 50 = 180

Combine like terms

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-------------------------------------------------

If line a parallel to line b then 5x - 16 = 74

Solve for x

5x - 16 = 74

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3 years ago
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