Jennifer brought $24.75 to the base ball game. She spent $12.45 on drinks and snacks. How much money does she have left over
1 answer:
Think of it this way. You have 5 apples. You eat 2. How many do you have left? Three. How? Well, you took away two from five, or you subtracted them (5-2) and got 3. We will do the same here.
If it’s the decimal places that confuse you, fear not. You subtract them just the same as you would normal numbers. I added a picture and labelled which numbers you subtract from which to make it easier if that’s the problem. Hope this helped.
The answer is $12.30 :)
If it’s the decimal places that confuse you, fear not. You subtract them just the same as you would normal numbers. I added a picture and labelled which numbers you subtract from which to make it easier if that’s the problem. Hope this helped.
The answer is $12.30 :)
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Eight *(a number) plus 5*(another number) is -13.
translates to:
8(x) + 5(y) = -13
The sum of (the number) and (the other number) is 1.
translates to:
(x) + (y) = 1
We have a system of two equations involving two unknowns: x and y.
We can easily solve the system using Substitution or Elimination. Let's use Elimination this time.
We'll multiply the second equation by -8 so that the x's match up.
When we add the equations together, the x's will fall out of the equation, summing to zero. The 5y and -8y will sum to -3y and the right hand side will sum to -21.
Divide by -3,
Plug back into one of your original equations to find the value of x,
Subtract 7,
translates to:
8(x) + 5(y) = -13
The sum of (the number) and (the other number) is 1.
translates to:
(x) + (y) = 1
We have a system of two equations involving two unknowns: x and y.
We can easily solve the system using Substitution or Elimination. Let's use Elimination this time.
We'll multiply the second equation by -8 so that the x's match up.
When we add the equations together, the x's will fall out of the equation, summing to zero. The 5y and -8y will sum to -3y and the right hand side will sum to -21.
Divide by -3,
Plug back into one of your original equations to find the value of x,
Subtract 7,