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tatiyna
2 years ago
15

The figure, polygon ABCD is dilated by a factor of 2 to produce A B C D with the origin as the center of dilation

Mathematics
1 answer:
cestrela7 [59]2 years ago
7 0

In the polygon ABCD, the production of point A' and point D' is (-2,-2)  and (4,-2) respectively.

<h3>What is the transformation rule?</h3>

In coordinate planes, the rule of transformation involves interchanging the x and y values on the plane such that:

\mathbf{(x,y) \to  (k_x, k_y)}

where;

  • k = scale factor

From the given information:

  • The scale factor = 2
  • the origin as a center of dilation for image vertices = (0, 0)

Now, using the coordinate vertices:

  • A = (-1, -1)
  • D = (2, -1)

The corresponding coordinate of the image vertices is as follows:

A(-1,-1) → A'(2 × (-1), 2 × (-1))

A' = (-2,-2)

D(2,-1) → A'(2 × (2), 2 × (-1))

D' = (4,-2)

Learn more about the transformation rule in coordinate planes here:

brainly.com/question/4251601

#SPJ1

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Gnesinka [82]

Answer:

540

Step-by-step explanation:

No matter what the shape, the total amount of degrees in the interior angles in a pentagon is 540. Hope this helps!

4 0
4 years ago
Freyda has a circular rug with a radius of 120 centimeters. The fringe on the outside edge of the rug needs to be replaced. What
Gnom [1K]

Answer:

The Fringe of the rug is 754 cm.

Step-by-step explanation:

Given:

radius = 120 cm

We need to find the fringe of the outside rug.

Solution:

Since the rug is in the circular form.

We can say that fringe of the outside edge of the rug can be equal to circumference of the circle.

Then we will find the Circumference of the circle.

Circumference of the circle is given 2 times 'π' times radius 'r'.

framing in equation form we get;

Circumference of the circle = 2\pi r

Circumference of the circle = 2 \times \pi \times 120 = 753.98 \approx 754\ cm

Hence the Fringe of the rug is 754 cm.

8 0
3 years ago
Aluate expressions<br> (5 + 3) •8-22
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Answer:

42

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7 0
3 years ago
Read 2 more answers
A rectangular box has a square base. The combined length of a side of the square base, and the height is 20 in. Let x be the len
aniked [119]

Answer:

a. V = (20-x) x^{2} in^{3}  

b . 1185.185 in^{3}

Step-by-step explanation:

Given that:

  • The height:  20  - x (in )
  • Let x be the length of a side of the base of the box (x>0)

a. Write a polynomial function in factored form modeling the volume V of the box.

As we know that, this is a rectangular box has a square base so the Volume of it is:

V = h *x^{2} in^{3}

<=> V = (20-x) x^{2}  in^{3}

b. What is the maximum possible volume of the box?

To  maximum the volume of it, we need to use first derivative of the volume.

<=> dV / Dx = -3x^{2} + 40x

Let dV / Dx = 0, we have:

-3x^{2} + 40x  = 0

<=> x = 40/3

=>the height h = 20/3

So  the maximum possible volume of the box is:

V = 20/3 * 40/3 *40/3

= 1185.185 in^{3}

7 0
3 years ago
What is the area of this triangle?
almond37 [142]
8(3) =12
Area= 12 units
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3 years ago
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