9514 1404 393
Answer:
a) V = 4w²h
b) SA = 4w² +10wh
c) SA = 4w² +37.5/w
d) C = 40w² +225/w
Step-by-step explanation:
The relevant formulas are ...
V = LWH
base area = LW
lateral area = H(2(L+W))
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a) The length is 4 times the width, so the volume is ...
V = (4w)(w)(h)
V = 4w²h
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b) The total surface area is the sum of the base area and the lateral area:
SA = base area + lateral area
SA = (4w)(w) + 2h(4w +w)
SA = 4w² +10wh
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c) The volume is 15 m³, so the height in meters in terms of the width in meters is ...
15 = 4w²h
h = 15/(4w²)
Then the surface area is ...
SA = 4w² +10w(15/(4w²))
SA = 4w² +37.5/w
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d) The equation we have for surface area has one term for base area and a second term for lateral area. We can apply the cost factors to those terms to get the cost of materials:
C = 10(4w²) +6(37.5/w)
C = 40w² +225/w
Answer:
Quadratic polynomial is x^2 - x - 20
It would be 9/8
Hope this helps!
You get 3x + 4x, +4- -3,and +3 + 4
The area is found by base x height
To find the missing height in the first one you divide 147 by 15 3/4 and get 9 1/3.
To find the missing base in the second one you divide 140 5/8 by 11 1/4 and get 12 1/2.
To find the missing height in the third one you divide 151 3/16 by 10 1/4 and get 14 3/4.
Make me brainliest ! :)
