Answer: The father is 37 years and the son is 7 years
Step-by-step explanation:
Let x represent the present age of the father.
Let y represent the present age of the son.
Three years hence a father will four times as old as his son will be. This means that
x + 3 = 4(y + 3)
x + 3 = 4y + 12
x - 4y = 12 - 3
x - 4y = 9- - - - - - - - - - - - - - - -1
Before two years he was seven times as old as his son was. This means that
(x - 2) = 7(y - 2)
x - 2 = 7y - 14
x - 7y = - 14 + 2
x - 7y = - 12- - - - - - - - - - - - - - -2
Subtracting equation 2 from equation 1, it becomes
3y = 21
y = 21.3 = 7
Substituting y = 7 into equation 1, it becomes
x - 4 × 7 = 9
x - 28 = 9
x = 9 + 28
x = 37
Answer:
Odds against the events are 7/9.
Step-by-step explanation:
It is given that:
Odds in favor of event = 2 : 9 or 2/9
Let,
These odds are out of 1.
The odds against the event would be
Odds against = 1 - 2/9
Odds against = 
Odds against = 
Therefore,
Odds against the events are 7/9.
The factors of 10 are 1, 2, 5, and 10. You can also look at this the other way around: if you can multiply two whole numbers to create a third number, those two numbers are factors of the third. 2 x 5 = 10, so 2 and 5 are factors of 10. 1 x 10 = 10, so 1 and 10 are also factors of 10.
she went to 5 diffrent places sooooo yuh and this makes absolutly no sense
Answer:
The probability that a student taking only math will get picked is approximately 29%
Step-by-step explanation: This is because out of the total number of students taking math (95), 52 of such students are also taking science. In order to get the number of students only taking math you have to do 95-52=43 and to put that against the amount of total students the ratio would be 43:147 or 42/147 and if you plug 42/147 into a calculator you will recieve a long decimal that you can then round to 29%.
