(x+a)^4 = ^4C_0 x^4 + ^4C_1 x^{4-1} a + ^4C_2x^{4-2}a^2 + ^4C_3x^{4-3}a^3 + ^4C_4x^{4-4}a^4
= x^4 + 4x^3a + 6x^2a^2 + 4xa^3 + a^4
Answer:
a. 1/5
b. (3, 3/5)
c. 1/5x = y
Step-by-step explanation:
Remember: (x, y)
0.5 = 1/2
(1/2, 1/10) = 1/10 ÷ 1/2 = 1/10 • 2 = 1/5, you can divide y/x = constant of proportionality. 1/10 ÷ 1/2.
1 2/5 = 7/5
(7, 7/5) = 7/5 ÷ 7 = 7/5 • 1/7 = 1/5, y/x = constant of proportionality. 7/5 ÷ 7.
- a. 1/5 is the constant of proportionality
- b. (3, 3/5) because 3/5 ÷ 3 or 3/5 • 1/3 = 1/5.
- c. 1/5x = y
Use the chain rule.
Let u = 25sin²(x), such that dy/dx = dy/du · du/dx
