Question

2}" alt="\sqrt[3]{x}=\sqrt[5]{32}" align="absmiddle" class="latex-formula">
why can't i just cube both sides, therefore kick the x out of the cubic root, and then i would have
$x = \sqrt{32} \\then \\x = \sqrt{16 * 2}\\x = 4\sqrt{2}$

Answer 1

Answer:

$x = 8$

Step-by-step explanation:

${x}^{ \frac{1}{3} } = {32}^{ \frac{1}{5} }$

${( {x}^{ \frac{1}{3} } )}^{3} = {( {32}^{ \frac{1}{5} } )}^{3}$

${x}^{1} = \sqrt[5]{ {32}^{3} }$

$x = \sqrt[5]{32768}$

$x = 8$