Answer:
The roots of any quadratic equation is given by using: x = [-b +/- sqrt(-b^2 - 4ac)]/2a. Write down the quadratic in the shape of ax^2 + bx + c = zero. If the equation is in the shape y = ax^2 + bx +c, honestly replace the y with zero. that is achieved because the roots of the equation are the values where the y axis is same to 0.
The equation is y=2x-2
To find the x-value you take any two pairs of value such as (-2,-3) and (0,-2) and you just use y1-y2/x1-x2. And for y-value you just see when x is zero
Answer:
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Step-by-step explanation:
4x² - 3, x less than/equal to 0
Step-by-step explanation:
y = (-1/2)[(x+3)^½]
(x+3)^½ = -2y
Square both sides,
(x+3) = (-2y)²
x+3 = 4y²
x = 4y²-3
Interswitch x and y
Inverse is 4x²-3
Domain of inverse is the range of f.
The range of f is less than/equal to 0
Because at x = -3, f(x) = 0
For x > -3, f(x) is negative
Domain of inverse is x less than/equal to 0
Answer:
-(6) x 8
ans: - 48
I believe that is the ans:
