Answer:
The correct option is;
90 degrees counterclockwise rotation
Step-by-step explanation:
The coordinates of the preimage before rotation = K(17, -12)
The coordinate of the image of the preimage after rotation = K'(12, 17)
Therefore, the rotation transformation, transforms, the preimage (x, y) to the image (-y, x), which is equivalent to a rotation of 90 degrees counterclockwise
Answer:
18
Step-by-step explanation:
I think the attached phôt below is your full question.
<u>And here is my answer: </u>
Surface area of a triangular prism = hight * area of the base
Here we have:
- h= 12
- Area of the base = 1/2 *2* 1.5 = 1.5
=> Surface area = 12*1.5 = 18
we know that a₁ = 1, and aₙ = aₙ₋₁ + 2, is another way of saying, we add 2 to get the next term, namely, 2 is the common difference.
![\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=1\\ d=2\\ n=7 \end{cases} \\\\\\ a_7=1+(7-1)2\implies a_7=1+12\implies a_7=13](https://tex.z-dn.net/?f=%5Cbf%20n%5E%7Bth%7D%5Ctextit%7B%20term%20of%20an%20arithmetic%20sequence%7D%0A%5C%5C%5C%5C%0Aa_n%3Da_1%2B%28n-1%29d%5Cqquad%0A%5Cbegin%7Bcases%7D%0An%3Dn%5E%7Bth%7D%5C%20term%5C%5C%0Aa_1%3D%5Ctextit%7Bfirst%20term%27s%20value%7D%5C%5C%0Ad%3D%5Ctextit%7Bcommon%20difference%7D%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Aa_1%3D1%5C%5C%0Ad%3D2%5C%5C%0An%3D7%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0Aa_7%3D1%2B%287-1%292%5Cimplies%20a_7%3D1%2B12%5Cimplies%20a_7%3D13)
Answer:
15=-6c-3d
Step-by-step explanation:
If 15=-3(2c+d)
=15=(-3×2c) - (-3×d)
=15=-6c-3d
You know you have to draw the triangles right?