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3 years ago

How do I find a7? Currently getting a even #

Mathematics

1 answer:

Katarina [22]3 years ago

5 0

we know that a₁ = 1, and aₙ = aₙ₋₁ + 2, is another way of saying, we add 2 to get the next term, namely, 2 is the common difference.

$\bf n^{th}\textit{ term of an arithmetic sequence}
\\\\
a_n=a_1+(n-1)d\qquad
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\[-0.5em]
\hrulefill\\
a_1=1\\
d=2\\
n=7
\end{cases}
\\\\\\
a_7=1+(7-1)2\implies a_7=1+12\implies a_7=13$

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15. The length of each edge of a regular tetrahedron,

grigory [225]

Slant height of tetrahedron is=6.53cm

Volume of the tetrahedron is=60.35 $\mathrm{cm}^{3}$

Given:

Length of each edge a=8cm

To find:

Slant height and volume of the tetrahedron

<u>Step by Step Explanation: </u>

Solution;

Formula for calculating slant height is given as

Slant height= $\sqrt{\frac{2}{3}} a$

Where a= length of each edge

Slant height= $\sqrt{\frac{2}{3}} \times 8$

= $\sqrt{0.6667} \times 8$

= $0.8165 \times 8$ =6.53cm

Similarly formula used for calculating volume is given as

Volume of the tetrahedron= $\frac{a^{3}}{6 \sqrt{2}}$

Substitute the value of a in above equation we get

Volume= $\frac{8^{5}}{6 \sqrt{2}}$

= $\frac{512}{6 \sqrt{2}}$

= $\frac{512}{6 \times 1.414}$

Volume= $512 / 8.484$ =60.35 $\mathrm{cm}^{3}$

Result:

Thus the slant height and volume of tetrahedron are 6.53cm and 60.35 $\mathrm{cm}^{3}$

7 0

3 years ago

Which student's work is correct? Explain please

Lunna [17]

Step-by-step explanation:

Wendy

-20 = x/2 + 7

-20 -7 = x/2 + 7 -7

-27 = x/2

-54 = x

x = -54

because it's math rule

8 0

3 years ago

"You measure 34 dogs' weights, and find they have a mean weight of 67 ounces. Assume the population standard deviation is 13.5 o

liraira [26]

Answer:

The 95% confidence interval for the true population mean dog weight is between 62.46 ounces and 71.54 ounces.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96*\frac{13.5}{\sqrt{34}} = 4.54$

The lower end of the interval is the sample mean subtracted by M. So it is 67 - 4.54 = 62.46 ounches.

The upper end of the interval is the sample mean added to M. So it is 67 + 4.54 = 71.54 ounces.

The 95% confidence interval for the true population mean dog weight is between 62.46 ounces and 71.54 ounces.

7 0

3 years ago

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goblinko [34]

Answer:Albert spent more on video games and 1/2>0.4

But Rosa spent more on pizza 2/5>.25

Step-by-step explanation: Rosa spent most of her allowance while Albert spent the least amount so Rosa spent more

5 0

2 years ago

Help I can't fail! pleaseeeee

VLD [36.1K]

Answer:

Step-by-step explanation:

I believe it's C.33 because if 4×33=132 the rest are smaller and one of the is equal,

So in my opinion It's 33

5 0

3 years ago