Twice the difference between x and k is 2(x-k)
The expression for the distance the car travels after t seconds is d = 200t + 50t²
<h3>Equation of motion </h3>
From the question, we are to write an expression for the distance the car travels after t seconds
From the given information,
The equation for the motion of an object with constant acceleration is
d = vt + 0.5at²
For the race car,
v = 200 ft/s
a = 100 ft/s²
Putting the parameters into the equation, we get
d = 200t + 0.5(100)t²
d = 200t + 0.5 ×100)t²
d = 200t + 50t²
Hence, the expression for the distance the car travels after t seconds is d = 200t + 50t²
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Answer:
both fireworks will explode 4.5 seconds after Firework B launches
Step-by-step explanation:
Given;
speed of firework A,
= 360 ft/s
speed of firework B,
= 340 ft/s
If the two fireworks explodes at the same height, then the height attained by the two fireworks are equal.
let the distance traveled by each firework before explosion = d
Distance = speed x time
Distance A = Distance B
speed A x time = speed B x time
let the time both fireworks explodes after Firework B launches = t
(
) t = (
) t
360t = 340t
if firework B is launched 0.25 s before Firework A, for the time of the two fireworks to be equal since we are considering time (t) after 0.25 seconds, we will have;
360(t-0.25) = 340t
360t - 90 = 340t
360 t - 340 t = 90
20 t = 90
t = 90/20
t = 4.5 seconds
Therefore, both fireworks will explode 4.5 seconds after Firework B launches
Answer:
22 people saw an horror movie
Step-by-step explanation:
Total people who attended the Sunday matinee = 48
People who saw romantic comedy = 3/8 of 48
= 3/8 × 48
= (3*48) / 8
= 144 / 8
= 18 people
People who saw action movie = 1/6 of 48
= 1/6 × 48
= 48/6
= 8 people
People who saw horror movie = x
Total people who attended the Sunday matinee = People who saw romantic comedy + People who saw action movie + People who saw horror movie
48 = 18 + 8 + x
48 = 26 + x
Subtract 26 from both sides
48 - 26 = 26 - 26 + x
22 = x
x = 22 people
22 people saw an horror movie
Answer:
The method of solving "by substitution" works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, "substituting" for the chosen variable and solving for the other. Then you back-solve for the first variable.
Step-by-step explanation:
Hope this helps you