54, 36, 24 are the 1st 3 element of a geometric progression with 2/3 as a common ratio: PROOF:
the 1st term is 54, (a₁= 54) the 2nd term a₂ = 24, then
(a₂ = a₁.r) or 36 = 54.r → r= 36/54 = 2/3. Same logique for the 3rd term.
So 2/3 is common ratio. We know that :U(n) = a.(r)ⁿ⁻¹. Then if a =54 and r = x (given by the problem), then f(x) = 54.xⁿ⁻¹
n, being the rank of any element of this geometric progression
Answer:
B
Step-by-step explanation:
It’s the only one with sides that correlate
SOLUTION:
Height of tree = 8.194 metres
Height of tree = 8.2 metres ( to the nearest tenth of a metre )
Therefore, the answer is:
The height of the tree is 8.2 metres when rounded to the nearest tenth of a metre.
Hope this helps! :)
Have a lovely day! <3
Answer: 5 63/100
Since the numerator is greater than the denominator, we got an IMPROPER fraction. So we can also express it as a MIXED NUMBER, although we know that 563/100 is also equal to 5 63/100 when written as a mixed number.
