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Tju [1.3M]
3 years ago
12

If a rectangular poster has an area of

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
8 0
2x ^2 - 9x + 10=\\
2x^2-4x-5x+10=\\
2x(x-2)-5(x-2)=\\
(2x-5)(x-2) \Rightarrow C
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xz_007 [3.2K]

Answer:

5.097

Step-by-step explanation:

4 0
3 years ago
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$4000 for 2years at 5% compounded quarterley
NeTakaya
\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4000\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, meaning 4 times}
\end{array}\to &4\\

t=years\to &2
\end{cases}
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3 years ago
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Answer:

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7 0
3 years ago
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rodikova [14]

Answer:

y = 2

Step-by-step explanation:

(x)(y) = k    Inverse relationship

(4)(3) = k

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7 0
3 years ago
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a photo album contains small and large photographs. Each large photograph has side lengths that are twice the side lengths of ea
zysi [14]
Take the area of the small photograph and divide it by four, assuming it's a square, each side would then be 6 inches. The large photograph has double the side length of the small one, so 6 multiplied by 2 is 12. To find the area of the large (square) photograph, multiply 12 by 12 as two of the sides, and the area of the large photo is 144 square inches
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3 years ago
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