Question

Determine 7th term in the geometric sequence whose first term is 5 and whose common ratio is 2.

Answer 1

Answer: 320

Step-by-step explanation:

$a_n=a_1(r)^{n-1}\quad \text{where}\ a_1\ \text{is the first term, r is the ratio, n is the term}$

$a_7=5(2)^{7-1}$

   $=5(2)^{6}$

   $=5(64)}$

   $=320$

Answer 2

Answer:

The 7th term in Geometric Sequence is 320

Step-by-step explanation:

Given : the geometric sequence whose first term is 5 and whose common ratio is 2.

To Find : 7th term

Solution :

Using the formula of Geometric Sequence :

$a_{n} =a_{1} *r^{n-1}$    --(A)

Since,

$a_{1}=5$

r =2

n = 7 (term no. need to calculate)

Putting these values in ---(A)

⇒$a_{7} = 5*2^{7-1}$

⇒$a_{7} = 5*2^{6}$

⇒$a_{7} = 5*64$

⇒$a_{7} =320$

Hence the 7th term in Geometric Sequence is 320