We're minimizing

subject to

. Using Lagrange multipliers, we have the Lagrangian

with partial derivatives

Set each partial derivative equal to 0:

Subtracting the second equation from the first, we find

Similarly, we can determine that

and

by taking any two of the first three equations. So if

determines a critical point, then

So the smallest value for the sum of squares is

when

.
H(h(x)) means to use the entire function h(x) as the x value in the function h(x)..
h(h(x)) = (x²+1)² + 1
= (x²+1)(x²+1) + 1
= (x^4 + x² + x² + 1) + 1
= x^4 + 2x² + 2
g(h(x)) means to use the entire function h(x) as the x value in the function g(x)..
g(h(x)) = 3(x² + 1)
= 3x² + 3
g(h(x))
Answer:
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Answer: x=5
Step-by-step explanation:
i’m not sure if that’s what you meant. there’s not much info.