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Virty [35]
3 years ago
12

Plz answer seriously and you will get 15 points and possibly a brainliest.

Mathematics
1 answer:
irina1246 [14]3 years ago
8 0

Just saying, this angle is a 45 degree angle.  

and the X on both is   '-1'

I think?

hope this helps. im not good at math..- :)

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Sue's teacher asked her to find 42.6 divided by ten to the power of two. How many places and in which direction should Sue move
algol [13]
Hey You!

Ten to the power of two = 100

So, when 42.6 is divided by 100, Sue should move the decimal 2 places to the left (before the 4).

42.6 ÷ 100 = 0.426
8 0
4 years ago
Read 2 more answers
Please help. I've been trying to figure this out for an hour and I still don't understand how it's 72. I feel really stupid beca
rosijanka [135]

Answer:

C. 72\pi

Step-by-step explanation:

The radius of the circle is 24 units, then the area of the whole circle is

\pi r^2=\pi \cdot 24^2=576\pi \ un^2.

The shaded circle is limited by 45° angle, so its area is

\dfrac{45}{360}=\dfrac{1}{8}

of the area of the whole circle.

The area of the shaded circle is

\dfrac{1}{8}\cdot 576\pi =72\pi \ un^2.

3 0
3 years ago
Haruka hiked several kilometers in the morning. She only hiked 6 kilometers in the afternoon, which was 25 percent less she had
Allisa [31]
6km is 3/4 of her morning speed so 6/(3/4)=6×4/3=8km. Total distance=6+8=14km.
5 0
3 years ago
Read 2 more answers
Which statement is true about the solution ?
Harrizon [31]

Answer:

There are no real solutions to this equation

Step-by-step explanation:

4 0
3 years ago
Persons taking a 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a
Alina [70]

Given:

30-hour review course average a score of 620 on that exam.

70-hour review course average a score of 749.

To find:

The linear equation which fits this data, and use this equation to predict an average score for persons taking a 57-hour review course.

Solution:

Let x be the number of hours of review course and y be the average score on that exam.

30-hour review course average a score of 620 on that exam. So, the linear function passes through the point (30,620).

70-hour review course average a score of 749. So, the linear function passes through the point (70,749).

The linear function passes through the points (30,620) and (70,749). So, the linear equation is:

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-620=\dfrac{749-620}{70-30}(x-30)

y-620=\dfrac{129}{40}(x-30)

y-620=\dfrac{129}{40}(x)-\dfrac{129}{40}(30)

y-620=\dfrac{129}{40}(x)-\dfrac{387}{4}

Adding 620 on both sides, we get

y=\dfrac{129}{40}x-\dfrac{387}{4}+620

y=\dfrac{129}{40}x+\dfrac{2480-387}{4}

y=\dfrac{129}{40}x+\dfrac{2093}{4}

We need to find the y-value for x=57.

y=\dfrac{129}{40}(57)+\dfrac{2093}{4}

y=183.825+523.25

y=707.075

y\approx 707.1

Therefore, the required linear equation for the given situation is y=\dfrac{129}{40}x+\dfrac{2093}{4} and the average score for persons taking a 57-hour review course is 707.1.

4 0
3 years ago
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